Remove all number that comes after in cell array

Hello again, I have a 45x1 cell 'ddindexcell' with numbers of different dimensions. Then I have a list of numbers 'indend2'.

What I'd like to achieve is to remove all the numbers that comes after indend2, if found in the cell.

Example:

A = [1, 2, 3, 4, 5] B = [3, 59, ... ]

[20]

[57, 58, 59, 60]...

The output would be:

Output = [1, 2, 3]

[20]

[57, 58, 59]

Perhaps changing it into an array would make the whole process friendlier, but I'm not sure.

How can I acheive this? Thanks in advance.

[Jorg Woehl]

Hi Jonathan, just to make sure I understand your problem correctly: I can see how B is supposed to act on the cell array A if the number listed in B is found in the cell of A. And if it is not found in A (such as in [20]), are the next cells of A simply skipped until the number listed B (i.e. 59 in your example) is found in a subsequent cell of A?

[Jonathan Cheong]

Hi Jorg,

Yes that's correct

Answer 1

[Jan]

With some bold guessing:

A = {[1, 2, 3, 4, 5],  [20],  [57, 58, 59, 60]};
B = [3, 59];

iB = 1;
for iA = 1:numel(A)                % Loop over elements of A
    index = find(A{iA} == B(iB));  % Search current B
    if ~isempty(index)             % If a match is found:
        A{iA} = A{iA}(1:index);    % Crop current A
        iB    = iB + 1;            % Select next B
    end
end

[Jonathan Cheong]

Yes, works perfectly thanks!