NCHOOSEK - What am I doing wrong?

V = nchoosek({CRY,DXY,GOLDS,USCRWTIC,USGG2YR,USGG10YR},4);
for i= 1:15;
A{i} = V(i,:);
end;
Basically, I would need to create A1 to A15 containing the 'i' line of the matrix V. For example:
V = [1 2 3 4 ; 5 6 7 8 ; 9 0 1 2]
I would need
A1 = [1 2 3 4]
A2 = [5 6 7 8]
A3 = [9 0 1 2]
I've been searching for this for all day >.<

 Respuesta aceptada

Image Analyst
Image Analyst el 25 de Mayo de 2013

1 voto

Sure, if you want to regress, just run this demo (where I made up some arbitrary values):
CRY = rand(1, 20);
DXY = rand(1, 20);
GOLDS = rand(1, 20);
USCRWTIC = rand(1, 20);
USGG2YR = rand(1, 20);
USGG10YR = rand(1, 20);
V = nchoosek({CRY,DXY,GOLDS,USCRWTIC,USGG2YR,USGG10YR},4)
for i= 1:15
A{i} = V(i,:);
end
y = sin(1:20);
% Regress y against A{1}
% Get one cell array of 4 cells from the first element of A
caRowOne = A{1}
% Extract just the first of those 4 cells.
xTraining = caRowOne{1}
% Plot training data.
plot(xTraining, y, 'bo');
hold on;
% Do a fit to a line.
coefficients = polyfit(xTraining, y, 1);
% See how well we did.
x = linspace(min(xTraining(:)), max(xTraining(:)), 40);
fittedY = polyval(coefficients, x);
plot(x, fittedY, 'r-', 'LineWidth', 2);
grid on;
title('Y vs. A{1}', 'FontSize', fontSize);
xlabel('X', 'FontSize', fontSize);
ylabel('Y', 'FontSize', fontSize);

1 comentario

Simon
Simon el 26 de Mayo de 2013
Pretty cool stuff Brah! I will try to loop this for all 15 combinations and then a p-value, F and t-test for each. Thanks a lot!

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Más respuestas (4)

Azzi Abdelmalek
Azzi Abdelmalek el 24 de Mayo de 2013
Editada: Azzi Abdelmalek el 24 de Mayo de 2013

1 voto

V = [1 2 3 4 5 6 7 8 9 0 1 2];
V=reshape(V,4,[]);
for i= 1:3
A{i} = V(:,i)';
end

6 comentarios

Simon
Simon el 24 de Mayo de 2013
The reshaping part works fine, but it does not create any variable..
Your variables are
A{1}
A{2}
A{3}
Simon
Simon el 24 de Mayo de 2013
Actually it gives me a variable called A with cell(1,1) = 1 5 9 2 , cell(2,1) = 6 0 3 7 and cell (3,1) = 1 4 8 2 :S
Azzi Abdelmalek
Azzi Abdelmalek el 24 de Mayo de 2013
Why do you want to create A1,A2 and A3, while one variable A is enough ?
If you insist to create A1,A2 and A3 (which is not recomanded)
V = [1 2 3 4 5 6 7 8 9 0 1 2];
V=reshape(V,4,[]);
for i= 1:3
eval([ sprintf('A%d',i) '= V(:,i)'''])
end
Jan
Jan el 25 de Mayo de 2013
@Simon: Don't use EVAL. Creating A1, A2, ... is a bad programming pattern and therefore the most cited question from the FAQ: FAQ: How can I create A1, A2, ... in a loop .
Staying with the original matrix and using V(i, :) would be much more direct and efficient instead of inserting indirect intermediate copies to a bunch of variables, which require crude tricks to be access automatically.

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Jan
Jan el 25 de Mayo de 2013

1 voto

V(i, :) is perfect already. Are you sure that there is any reason for adding a level of abstraction by splitting the matrix to a bunch of vectors?

2 comentarios

Simon
Simon el 25 de Mayo de 2013
Will i be able to perform regression on each cell of A(i) with another variable? (cell 1,1 with Y , then Cell 1,2 with Y , etc)
Jan
Jan el 25 de Mayo de 2013
@Simon: It is very likely, that you can perform the regression even with the original matrix directly. The most Matlab commands can handle a matrix input and process the operations for the subvectors automatically. When you post the code you want to apply, more detailed suggestions are possible.
When you want to access the contents of a cell, use the curly braces: A{1} etc.

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Simon
Simon el 26 de Mayo de 2013

0 votos

Thanks everyone! If could accept everyone's answer i would..

3 comentarios

Randy Souza
Randy Souza el 31 de Mayo de 2013
Simon, you can always vote for the other answers!
Simon
Simon el 31 de Mayo de 2013
Editada: Randy Souza el 31 de Mayo de 2013
How?
Randy Souza
Randy Souza el 31 de Mayo de 2013
There should be a triangle with "x Votes" under the profile picture for the answerer. Click that and it should change to "(x + 1) Votes"

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