Replace character in string/cell with the character above it
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Dora de Jong
el 11 de Mzo. de 2021
Comentada: Dora de Jong
el 11 de Mzo. de 2021
String/cell example: --> real string/cell is very long
a= { 'a' ; 'b' ; 'c' ; 'b'}
Wanted outcome:
a_new= { 'a' ; 'a' ; 'c' ; 'c'}
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the cyclist
el 11 de Mzo. de 2021
Editada: the cyclist
el 11 de Mzo. de 2021
The general rule is not perfectly clear to me, from your small example. Do you mean that you want the even-numbered elements to be replaced? If so, then
anew = a;
a(2:2:end) = a(1:2:end-1);
If not, maybe you could explain in a little more detail.
3 comentarios
the cyclist
el 11 de Mzo. de 2021
Editada: the cyclist
el 11 de Mzo. de 2021
Here is one way:
a = { 'a' ; 'b' ; 'c' ; 'b' ; 'h' ; 'g' ; 'b'};
replace_idx = find(strcmp(a,'b'));
a_new = a;
a_new(replace_idx) = a_new(replace_idx-1);
This will not work if 'b' is the first element, so you will need to modify this algorithm in that case. But you haven't given info on what you want to do then.
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Jan
el 11 de Mzo. de 2021
Editada: Jan
el 11 de Mzo. de 2021
Maybe:
a_new = a;
a_new(2:2:end) = a(1:2:end);
Or:
index = repelemt(1:2:numel(a), 1, 2):
a_new = a(index)
[EDITED] after your comment: "So every b wil be replaced with the character above it"
index = find(strcmp(a, 'b'));
a(index) = a(index - 1);
What about: {'a'; 'b'; 'b'} or {'b'} or {'b', 'a'}?
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