Fill an array according to the values of a different array

I have 2 arrays. one is A = 21x2 array and the other is B = 700x2 array.

Exemplary:

A=  24  33
    26  34
    27  33

In the end, B should be structured in such a way that the value from the 1st column is entered in B as often as it is in the second column (33 lines with "24") of A.

The second problem i've got is that I want to fill an array with the output of a function but hence the function is using

Tiefe=normrnd(mu_Tiefe, sigma_Tiefe);

I want to create new random numbers for every cell of the array.

Is it possible to do that without a loop or do I have to use a loop for that?

Or is it mayby easier to create arrays containing the random numbers and pass the arrays to the function?

Answer 1

[Aghamarsh Varanasi]

Hi Patrick,

Here is a small script for filling array based on another array.

% Lets say
%A = 24     3
%    22     5
%    34     2

A = [24 3; 22 5; 34 2];
B = zeros(1,sum(a(:,2)));

count = 1;
for i = 1:length(A)
    idx = zeros(1,length(B));
    idx(count : count + A(i,2)) = 1;
    B(logical(idx)) = A(i,1);
    count = count + A(i,2);
end

For generating an array of random numbers refer to this documentation page.

[Patrick Benz]

Thx for the small script.

Is there maybe a different approach to do it without a loop?

For the second case, I think I didn't really point out what I was looking for. But I solved the the issue.

When using normrnd

normrnd(mu_Tiefe, sigma_Tiefe,Anzahl,1)

the third and fourth parameter are for the size of the array.