Most efficient way of creating variables

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James Rodriguez
James Rodriguez el 12 de Mzo. de 2021
Comentada: James Rodriguez el 13 de Mzo. de 2021
I have 8 matrices, (13x10) ,which contain velocites of a flow within a channel (V1,V2.....V8). For each of these I have extarcted the lasts columns using the following :
E1 = V1(:,10);
E2 = V2(:,10);
E3 = V3(:,10);
......
E8 = V8(:,10);
I read the following https://uk.mathworks.com/matlabcentral/answers/57445-faq-how-can-i-create-variables-a1-a2-a10-in-a-loop which mentions that dynamic variable names should be avoided where possible.
In accordance, I attempted to try what the post suggested (Making one matrix with the 8 columns (E):
E = zeros(13,8); % Each column to be replaced by the last columns of V1,V2..V8
for i = [1:8];
E(i) = V(i)(:,10); % Trying to assign final columns of V1,V2..V8 to the columns of E8
end
However, I feel as if this is very far from the correct way of doing this. Any help is appreciated

Respuesta aceptada

Adam Danz
Adam Danz el 12 de Mzo. de 2021
Editada: Adam Danz el 12 de Mzo. de 2021
It's good that you're following that advice.
E = [V1(:,10), V2(:,10), . . ., Vn(:,10)]; % most efficient method of this list
If you want to use a loop, the variables have be to combined before hand,
V = {V1, V2, V3, . . ., Vn};
E = zeros(size(V1,1), numel(v));
for i = 1:numel(V)
E(:,i) = V{i}(:,10);
end
or, if the Vn matrices are all the same size,
V = cat(3, V1, V2, V3, . . ., Vn);
E = squeeze(V(:,10,:));
  1 comentario
James Rodriguez
James Rodriguez el 13 de Mzo. de 2021
Thank you very much! This is very useful information and I really appreciate the alternate methods.

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