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How to read matrix into a variable increment?

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MAIZATUL
MAIZATUL el 29 de Mayo de 2013
I have a matrix A that only have data on 1st column.
How can I write this matrix as increment
t = [0:1st row data :end of row data]
help, thank you.

Respuestas (2)

David Sanchez
David Sanchez el 29 de Mayo de 2013
Your question is not clear. Do you mean something like this?
A=zeros(10);
A(:,1)=rand(10,1);
B=sort(A);
Where B contains the data in A order from minimum value to maximum.
If you want to write that column in incremental form, such as
t=1:2:20
t =
1 3 5 7 9 11 13 15 17 19
You need the first and last term and the increment between each value, supposed to be constant, otherwise you can't do as you want. You can not write in incremental notation an array like
c = [1 3 4 8 17 19 23 58]
since the increment between any two consecutive terms is different from any other
  1 comentario
MAIZATUL
MAIZATUL el 29 de Mayo de 2013
my data in matrix is not constant increment. so it cant be done

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Muruganandham Subramanian
Muruganandham Subramanian el 29 de Mayo de 2013
e.g,
>> A=[1;2;3;4;5;6];
>> t = 0 : A(1,1) : A(end,1)
Are you expecting like this??
  3 comentarios
Muruganandham Subramanian
Muruganandham Subramanian el 29 de Mayo de 2013
Editada: Muruganandham Subramanian el 29 de Mayo de 2013
Is your A matrix will change randomly from time to time ?? Show ur code then?
if its having random data like below, e.g
>> A = [ 4; 2; 7; 90; 1; 34; 6; 34; 23;];
then
>> t = 0 : A(1,1): A(1,1) * size(A,1);
Try this
MAIZATUL
MAIZATUL el 29 de Mayo de 2013
its ok I solved it. A = [2.345, 4.543, 5.676... end}
t = [A(1:end)] thanks!

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