Extract first and last nonzero elemenents inside subarrays avoiding mat2cell

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Can somone please give me a hand?
I have a matrix A such as:
A = [0 0 1 2 0 5 0 0 6 0 3 0 ; 0 3 0 2 6 0 0 0 0 0 0 0];
I'd like to check where are the first and last nonzero values along my subarrays of 6 elements on each row. So the expected Output shoul be:
Out = [0 0 1 0 0 1 0 0 1 0 1 0 ; 0 1 0 0 1 0 0 0 0 0 0 0];
I know I can easilly use mat2cell to perform this but I'd like to avoid using this funciton.
Thank's for the help,
Santos

Respuesta aceptada

Bruno Luong
Bruno Luong el 22 de Mzo. de 2021
Editada: Bruno Luong el 22 de Mzo. de 2021
A = [0 0 1 2 0 5 0 0 6 0 3 0 ; 0 3 0 2 6 0 0 0 0 0 0 0];
b = reshape(A.',6,[]) ~= 0;
[m,n] = size(b);
[~,istart] = max(b,[],1);
[~,istop] = max(flip(b,1),[],1);
i = [istart; m+1-istop] + (0:n-1)*m;
B = zeros(size(b));
B(i) = b(i);
Out = reshape(B,flip(size(A))).'

Más respuestas (1)

DGM
DGM el 22 de Mzo. de 2021
I arbitrarily chose to avoid loops and find() and ended up with this ugly thing. It works, but I wouldn't call it elegant. I added some dummy values to the test array to demonstrate that it handles cases where there are no matches
A = [0 0 1 2 0 5 0 0 6 0 3 0 ; 0 0 0 0 0 0 0 0 0 0 0 0; 0 3 0 2 6 0 0 0 0 0 0 0];
A=reshape(A',6,[])'
matches=[sum(cumprod(A == 0,2),2)+1; 6-sum(cumprod(A == 0,2,'reverse'),2)];
matches=[[1:6 1:6]; matches']';
matches=matches(matches(:,2)>0 & matches(:,2)<7,:);
B=zeros(size(A));
B(sub2ind(size(A),matches(:,1),matches(:,2)))=1;
B=reshape(B',12,[])'
this yields:
B =
0 0 1 0 0 1 0 0 1 0 1 0
0 0 0 0 0 0 0 0 0 0 0 0
0 1 0 0 1 0 0 0 0 0 0 0
Again, I added the extra row

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