How to add a loop counter and respond to user input

Write a program that repeats the process of prompting the user to enter a positive number as long as the user correctly enters positive numbers when prompted. The program should count the number of numbers that the user successfully enters. As soon as the user types a negative number the program will print OK and shows the number of numbers that the user has successfully entered.

[Chris]

I already have this much.

a=10;
while a-1>0
  a=input('Please input an even number [even]: ', 's')
end

[Walter Roberson]

Why are you asking the user to enter even numbers when the homework requires entering positive numbers?

You are not checking to see whether the input is acceptable or not.

What should happen if the user enters 0? 0 is not positive, but it is also not negative (the termination condition)

Answer 1

[Vishal Rane]

When in doubt write a pseudo code:

1) Prompt user to enter something ( in ur case a number )

2) Accept number from user

3) Code checks if number is acceptable ( check for special chars, strings, etc)

4a) If valid number and positive, store it, repeat 1-4

4b) If valid number and negative, display 'OK', calculate and display count of stored numbers

4c) If invalid input, show prompt again ignoring user input or notifying him/her of the same

Answer 2

[Chetan Aswathanarayana]

function Sample()
Loop  = true;
Count = 0;
while(Loop)

      a = input('Please input a positive number: ');

      if a>=0
          Count = Count+1;
      else
              Loop = false;
      end

end

fprintf('Ok, the number of inputs enetered by the user is %d',Count);

end