Simple solution to a simple problem
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Hey, Im trying to write an algorithm to compute the integral of a user inputted function with limits. I wrote the following code:
function I=Simpson38(Fun,a,b)
N=3;
dif=1;
I1=0;
func=inline(Fun);
while dif>0.001
h=(b-a)/N;
Ia=(h*3/9)*(func(1)+func(N+1));
Ib=(h*3/9)*(2*sum(func(4:3:(N-2))));
Ic=(h*3/9)*(3*sum(func(2:3:(N-1)))+sum(fun(3:3:N-1)));
I2=Ia+Ib+Ic;
dif=(I1-I2)/I2;
I1=I2;
N=N*2;
end
I=I1;
When i run the code i get the following error: ??? Error using ==> inlineeval at 15 Error in inline expression ==> 1/(1+9*x.^2) Matrix dimensions must agree.
Error in ==> inline.subsref at 27 INLINE_OUT_ = inlineeval(INLINE_INPUTS_, INLINE_OBJ_.inputExpr, INLINE_OBJ_.expr);
Error in ==> Simpson38 at 9 Ib=(h*3/9)*(2*sum(func(4:3:(N-2)))); What could be the problem?
0 comentarios
Respuestas (1)
Richard Brown
el 14 de Jun. de 2013
Try
1./(1 + 9*x.^2)
i.e. a '.' before the division
2 comentarios
Richard Brown
el 16 de Jun. de 2013
Great! Please "accept" the answer so people browsing the forum knows it's been answered
Ver también
Categorías
Más información sobre Numerical Integration and Differential Equations en Help Center y File Exchange.
Productos
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!