Richard Brown

Massey University

Last seen: más de 1 año hace | Con actividad desde 2008

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Maths Lecturer at Massey University. Working on high performance computing and modelling. Professional Interests: numerical analysis, modelling, computer vision, mathematical biology

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Alternatives to Delaunay triangulation
As David Wilson suggested, use alphashape: U = csvread('Coords.txt'); shp = alphashape(U(:, 1), U(:, 2), U(:, 3)); plot(shp) ...

alrededor de 5 años hace | 1

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How to pass a method as a function handle
I think the issue is that to use the @ construction, the thing you're applying it to needs to be named function in scope. There ...

alrededor de 5 años hace | 0

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Singular Matrices: Is the Matlab algorithm for CONDITON NUMBER always stable ?
The algorithm for condition number uses the SVD, not LU factorisation and is perfectly stable.

alrededor de 5 años hace | 1

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3D Measurementm using matlab
You could try the computer vision toolbox, which has an interface to OpenCV I believe. Writing the whole thing from scratch is...

alrededor de 5 años hace | 0

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Taking Mean Of Specific Rows and Columns Within A Loop
You don't need a loop. Basic idea: extract column 2. Reshape it into a matrix with columns 1200 tall take the mean of each co...

alrededor de 5 años hace | 1

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Need to solve the differential equation for beam deflection and get the following plot
I think the problem you're having is not fully figuring out your solution before diving in and coding it. You have a differentia...

alrededor de 5 años hace | 2

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How to go around infinite recursions
I'm not sure the code you've written describes what you intend. It's going to create an unterminated recursion that will cause a...

alrededor de 5 años hace | 0

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need help with basic speed time graph plot
Your function needs to have elementwise powers, i.e. use .^ instead of ^ It's trying to do matrix powers of the vector of time ...

alrededor de 5 años hace | 1

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Random sampling of elements from an array based on a target condition in MATLAB
If your process is just to sample until you are within a tolerance of V_1 and you want things to be truly random, how about the ...

alrededor de 5 años hace | 1

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For a class object with a property that is an array of class objects, how to find the element in that array with highest property value
Your obj.population.fitness line returns comma separated values, not an array. So just enclose it in brackets: [M, I] = max(...

alrededor de 5 años hace | 1

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Non Zero element appear first with keeping the same size of the matrix?
here's a really naive way to do it: [m, n] = size(A); for i = 1:m k = find(A(i, :)) A(i, :) = [A(i, k), zeros(1, n -...

alrededor de 5 años hace | 1

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fitellipse.m
Fit ellipses to 2D points using linear or nonlinear least squares

casi 9 años hace | 18 descargas |

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nearestneighbour.m
Computes nearest neighbour(s) by Euclidean distance

casi 9 años hace | 14 descargas |

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How to create a sparse matrix with such specifications?
*edit* This version is wrong, but leaving so comment below makes sense density = 0.01; % For example m = 10000; n = 1000...

más de 11 años hace | 0

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count groups of elements and distances between them
A = [6 6 6 4 4 4 4 4 6 5 5 7 7 7 8 9 8 7 0 0 0 0]; x = diff([find(diff([0 ismember(A, [0 6]) 0]))]); L = x(1:2:end); ...

más de 11 años hace | 2

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Positive Semi-definite Matrix Problem
You're just going to have to live with it. Your matrix is PSD to double precision. If you look at the magnitude of the "zero" ei...

más de 11 años hace | 1

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vectorizing calculation of eigen values of a large multi-dimensional array
You'll get a bit of a performance boost simply by looping over linear indices rather than nesting (this is more than twice as fa...

más de 11 años hace | 0

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Reduced row echelon form technique
It'll be a difference between yours and MATLAB's choice of tolerance. Your matrix should be rank 2, however I notice that MATLAB...

más de 11 años hace | 0

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Evaluation of matrix element of a linear differential matrix equation by constrained least square fitting
Assuming you have multiple |X| and |X'| vectors that you're trying to fit your matrix to, your problem can be posed as a constra...

más de 11 años hace | 0

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displaying indexed values correctly
Similar to what you asked before, I think what you want is to find the |Vb| element that is closest to half of |Vb_ev|, and then...

más de 11 años hace | 0

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finding closest values in array
If I understand correctly, you want to find the |pH| value in your array closest to 4.756, and pull this value out, together wit...

más de 11 años hace | 5

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How can I create sparse symmetric positive definite linear system?
|sprandsym| is what you want. m = 50; density = 2/m; % for example rc = 0.1; % Reciprocal condition number A = spr...

más de 11 años hace | 1

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Sign differences in QR decomposition
It's only unique up to the signs of the rows of |R|. If you want to enforce positive diagonals of |R|, and thereby get a unique ...

más de 11 años hace | 3

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Output argument "Clus_Area" (and maybe others) not assigned during call to
Check that the line if AR > 0 is doing what you intend. This will only evaluate if all entries of |AR| are positive. T...

más de 11 años hace | 0

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How to use variable value as an input to the function?
You can very probably get away with just passing |template1| and |template2| themselves (not trying to create references to them...

más de 11 años hace | 0

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Why I'm keep getting these errors? Please help!
The error message says it all. You're only computing one derivative in |my_function|. You need to define |ys(1)| and |ys(2)|...

más de 11 años hace | 1

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How do I efficiently calculate a scalar distance with 3d geometry?
You should use |hypot|. It also has better numerical stability. *edit* sorry, you're in 3D. That obviously won't work. You c...

más de 11 años hace | 0

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Generating a particular sequnce of numbers
Also comparable, but not (quite) faster n = 1:(d*(d+1)/2); a = ceil(0.5*(-1 + sqrt(1 + 8*n))); out = a.*(a + 1)/2 - n...

más de 11 años hace | 2

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Generating a particular sequnce of numbers
Even faster: k = 1; n = d*(d+1)/2; out = zeros(n, 1); for i = 1:d for j = i:-1:1 out(k) = j;...

más de 11 años hace | 2

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please help with logical operators
replace all instances of |lenght| with |length|

más de 11 años hace | 0

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Richard Brown

Massey University

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