Matlab command window is blocked / or busy when I plot an animation
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Hello, Was just wondering if Matlab supports the below ?
below is the small snippet (say), I plot a figure and try to acheive animation in a while(1) loop:
function Example()
x=-5:.2:5;
y=sin(x);
h=plot(x,y);
axis([-2*pi 2*pi -1 1])
axis square
grid off
set(h,'EraseMode','xor','MarkerSize',18)
while(1)
for t=2:.1:7
drawnow
y=sin(x)*exp(-t);
set(h,'YData',y)
pause(0.05)
end
end
So I' am able to achieve th animation but can I do that witout locking the command window ? I don't want to block the command window. Could some one help me out on this please ?
1 comentario
Chetan Aswathanarayana
el 18 de Jun. de 2013
It would be Interesting, if somebody knows the answer for this one ?
Respuestas (4)
Sean de Wolski
el 18 de Jun. de 2013
Use a timer.
doc timer
I've written quite a few answers that have examples in them if you search through Answers' history.
0 comentarios
Karthuk
el 18 de Jun. de 2013
1 comentario
Jan
el 18 de Jun. de 2013
Please do not bump your question by posting a pseudo-answer. If the readers know an answer and find the time for typing it, they will do it voluntarily. But when the question appears on topmost position again, although there is no new information, the time for reading the question another time is wasted. Therefore I'd suggest to limit bumping for a time delay of 24, better 48 hours.
Jan
el 18 de Jun. de 2013
Matlab is a single threaded application (in theory). Using the TIMER Sean has suggested is a method to run a thread nearly in parallel. But the esiest way is to open another Matlab instance:
!matlab &
1 comentario
raym
el 13 de Abr. de 2018
Yes. The pause(i) blocks all the command window and blobks all running code.
Chetan Aswathanarayana
el 19 de Jun. de 2013
Thanks Sean, Picked up something from this today.
@Karthuk: Maybe this might help and was what you were looking for:
function Example()
x=-5:.2:5;
y=sin(x);
h=plot(x,y);
axis([-2*pi 2*pi -1 1])
axis square
grid off
set(h,'EraseMode','xor','MarkerSize',18)
t = timer('ExecutionMode','fixedRate',... %# Fire at a fixed rate
'Period',0.25);
t.TimerFcn = {@Do_It,h,x};
start(t);
end
function Do_It(obj,event,h,x)
for t=2:.1:7
drawnow
y=sin(x)*exp(-t);
set(h,'YData',y)
pause(0.04)
end
end
1 comentario
Sean de Wolski
el 19 de Jun. de 2013
I would lower the timer's period and then remove the for-loop from DO_it. You can calculat T based on the event's 'TasksExecuted' property.
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