Symbolic math toolbox- Jacobian of a function with respect to an other function?
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Maria Perdomo
el 24 de Jun. de 2013
Comentada: Sohini Sarkar
el 24 de Nov. de 2021
I would like to find the jacobian of:
f=[f(x1(t)...x6(t)); ... ;f6(x1(t)...x6(t))]
with respect to:
x(t)=[x1(t);...;x6(t)]
which function could I use?
Is it possible to differenciate a symbolic function with respect to an other symbolic function?
0 comentarios
Respuesta aceptada
Walter Roberson
el 25 de Jun. de 2013
No, it is not possible to differentiate with respect to a function. In a previous post several months ago I showed how that leads to a contradiction.
3 comentarios
Frederik Rentzsch
el 24 de Nov. de 2021
It seems to be possible since Release of R2021b.
syms x1(t) x2(t)
syms f1(x1,x2) f2(x1,x2)
f = [f1 f2];
jacobian(f,[x1 x2])
works as intended but after f1 and f2 are defined x1 and x2 are no symfun-objects anymore. Bug?
Sohini Sarkar
el 24 de Nov. de 2021
Also see Functional Derivative: Functional derivative (variational derivative) - MATLAB functionalDerivative (mathworks.com)
Más respuestas (1)
Alan Weiss
el 24 de Jun. de 2013
doc jacobian
Alan Weiss
MATLAB mathematical toolbox documentation
0 comentarios
Ver también
Categorías
Más información sobre Assumptions en Help Center y File Exchange.
Productos
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!