fopen problem help please

In this part of code
disp(filename)
fid=fopen([filename '.hea']);
disp('debug')
I have error
---WFDB/I0005 ->(its a display filename, i have in WFDB folder files I0005.hea and i0005.mat)
---Error using fopen
---First input must be a file name or a file identifier.
Please, help with fopen) (m2020 mac version)

2 comentarios

Stephen23
Stephen23 el 15 de Abr. de 2021
@Anton Gubrienko: please show the complete error message. This means all of the red text.
Walter Roberson
Walter Roberson el 15 de Abr. de 2021
I suspect that your filename variable is a cell array instead of a character vector or string scalar

Iniciar sesión para comentar.

Respuestas (1)

Ankriti Sachan
Ankriti Sachan el 20 de Abr. de 2021

0 votos

As Walter mentioned, I am also guessing that you are providing a folder name instead of a filename as the input to the fopen function. Please verify the same. Also, you can verify if any other file in the same folder is accessible using fopen.
I hope this answers your query.

4 comentarios

Walter Roberson
Walter Roberson el 20 de Abr. de 2021
It is unlikely that a name ending in .hea is a directory name. Not out of the question, but not likely.
Ankriti Sachan
Ankriti Sachan el 20 de Abr. de 2021
Editada: Ankriti Sachan el 20 de Abr. de 2021
Hi Walter, yes, even I believe .hea is not a directory name. However, I read a few resources that indicate that the filenames and the path provided might be incorrect for fopen() here. It might be a possibility that the path provided might be level below to the actual path where the files are located.
It seems like the .dat and .atr files are also read in the same way as the .hea files. Also, there are few comments that talk about reading these files in this post. Maybe those can help.
First input must be a file name or a file identifier
You do not get that message if you accidentally name a directory instead of a file.
mkdir junk_dir_for_test
[fid, msg] = fopen('junk_dir_for_test');
if fid < 0
warning('failed to open file because: "%s', msg);
else
fprintf('fopen of directory worked?\n');
fclose(fid)
end
Warning: failed to open file because: "Is a directory
[fid, msg] = fopen('junk_does_not_exist_for_test');
if fid < 0
warning('failed to open file because: "%s', msg);
else
fprintf('fopen of non-existent file worked?\n');
fclose(fid)
end
Warning: failed to open file because: "No such file or directory
[fid, msg] = fopen({'junk_does_not_exist_for_test'});
Error using fopen
First input must be a file name or a file identifier.
if fid < 0
warning('failed to open file named as cell because: "%s', msg);
else
fprintf('fopen of non-existent named as cell file worked?\n');
fclose(fid)
end
The only case you get the error message being observed is if the parameter passed to fopen() is not a character vector or string scalar.
In the context of
% fid=fopen([filename '.hea']);
then if filename were a cell array of character vectors instead of a character vector, you would get that problem.
Ankriti Sachan
Ankriti Sachan el 20 de Abr. de 2021
Sure, thanks for clarifying. That helps.

Iniciar sesión para comentar.

Categorías

Más información sobre File Operations en Centro de ayuda y File Exchange.

Etiquetas

Preguntada:

el 15 de Abr. de 2021

Comentada:

el 20 de Abr. de 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by