# for looop convert to arrayfun

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Question Mr el 29 de Abr. de 2021
Editada: Matt J el 30 de Abr. de 2021
I want to convert these for loops into an arrayfun. Always give me an error
"All of the input arguments must be of the same size and shape.
Previous inputs had size 31 in dimension 1. Input #5 has size 1"
nElec = length(M.lab);
EF(nElec,nElec) = 0;
for i = 1:nElec;
for j = 1:nElec;
EF(i,j) = 1 - ( ( (X(i) - X(j))^2 + ...
(Y(i) - Y(j))^2 + (Z(i) - Z(j))^2 ) / 2 );
end;
end;
I tried to create a new funciton:
function EF = gpuefg(X,Y,Z, maxiter)
EF(maxiter,maxiter) = 0;
for i = 1:maxiter;
for j = 1:maxiter;
EF(i,j) = 1 - ( ( (X(i) - X(j))^2 + ...
(Y(i) - Y(j))^2 + (Z(i) - Z(j))^2 ) / 2 );
end;
end;
end
And call it
EFG = gpuArray(EF);
.
.
.
EFG = arrayfun(@gpuefg,X,Y,Z, nElec, 'UniformOutput', false );
But not working, how should I do this?
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David Hill el 29 de Abr. de 2021
Please explain what you are trying to do. What are your inputs and expected outputs?
Question Mr el 29 de Abr. de 2021
Here is my original code: (not the whole is just the point)
nElec = length(M.lab);
EF(nElec,nElec) = 0;
for i = 1:nElec;
for j = 1:nElec;
EF(i,j) = 1 - ( ( (X(i) - X(j))^2 + ...
(Y(i) - Y(j))^2 + (Z(i) - Z(j))^2 ) / 2 );
end;
end;
output is a matrix
And I tried to create my own function for change two "for" loop
function EF = gpuefg(X,Y,Z, maxiter)
EF(maxiter,maxiter) = 0;
for i = 1:maxiter;
for j = 1:maxiter;
EF(i,j) = 1 - ( ( (X(i) - X(j))^2 + ...
(Y(i) - Y(j))^2 + (Z(i) - Z(j))^2 ) / 2 );
end;
end;
end
Output is matrix like in the original "EF(i,j)" (well that is the plan)
When I called:
EFG = gpuArray(EF);
...
EFG = arrayfun(@gpuefg,X,Y,Z, nElec, 'UniformOutput', false );
It's crashed but I dont know why,
EFG is a gpuArray,
X,Y,Z my function's inputs
nElec is my function's maxiter
So the point is, I want to swap these two "for loops" for one "arryfun"

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Matt J el 29 de Abr. de 2021
Editada: Matt J el 29 de Abr. de 2021
The way to do this with arrayfun, (which I don't think will be optimal here) would be,
[I,J]=ndgrid(gpuArray(1:nElec));
fun=@(i,j) 1 - ( ( (X(i) - X(j))^2 + (Y(i) - Y(j))^2 + (Z(i) - Z(j))^2 ) / 2 );
EF= arrayfun(fun,I,J);
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Question Mr el 30 de Abr. de 2021
I have another question. I tried you solution but I got this error:
"Use of functional workspace is not supported.
What should I do now? I've wroten the code into the .m file
Matt J el 30 de Abr. de 2021
Editada: Matt J el 30 de Abr. de 2021
Why did you Accept the answer if it didn't work? Why not just go with the other answer, which I told you should be better than arrayfun?

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### Más respuestas (1)

Matt J el 29 de Abr. de 2021
Editada: Matt J el 29 de Abr. de 2021
The more efficient way to do what you are attempting is with the 2 lines of code,
X=X(:); Y=Y(:); Z=Z(:);
EF = 1 - ( (X-X.').^2 + (Y-Y.').^2 + (Z-Z.').^2)/2 ;
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