finding maximum angle and managing data
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
h=130;
H=50;
i=1;
x=30:0.5:300;
AC=sqrt(x.^2+(h+H)^2);
AB=sqrt(x.^2+(h)^2);
th=acos((AB.^2+AC.^2-H^2)./(2*AB.*AC));
[thMax n]=max(th);
xthMax=x(n);
fprintf('Distance is %6.3ft at Maximum angle %6.3 deg\n',xthMax,thMax)
Hi , I have done this so far but now I get this
Distance is 153.000t at Maximum angle Distance is 153.000t at Maximum angle 0.162 deg how can I take away the repetition of the Distance and the angle is not 0.162 deg it should be 9.282 according to my calculations , do you see anything wrong thanks for the feedback >>
0 comentarios
Respuesta aceptada
Matt J
el 12 de Jul. de 2013
Editada: Matt J
el 12 de Jul. de 2013
Use acosd() if you want the result in degrees instead of radians.
I don't see the repetition you mention when I run your code, but make sure that xthMax and thMax are scalars.
2 comentarios
Matt J
el 12 de Jul. de 2013
And your fprintf call should probably look like this
fprintf('Distance is %6.3f at Maximum angle %6.3f deg\n',xthMax,thMax)
Más respuestas (0)
Ver también
Categorías
Más información sobre Numerical Integration and Differential Equations en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!