Hi,
I have time series given in gregorian time in seconds since 1992-01-01 00:00:00'. For example; 23853938,23853939...
How can i convert this gregorian time seconds to decimal years like 2010.544, 2010.545...

 Respuesta aceptada

Walter Roberson
Walter Roberson el 10 de Mayo de 2021
basetime = datetime('1992-01-01 00:00');
gtime = 23853938
t1 = basetime + seconds(gtime)
t2 = dateshift(t1, 'start', 'year')
t3 = dateshift(t1, 'end', 'year')
fy = year(t1) + (t1-t2)./(t3-t2)

4 comentarios

Walter Roberson
Walter Roberson el 10 de Mayo de 2021
This assumes fraction of actual year, taking into account leap year, not fraction of fixed length year.
Ahmet Hakan UYANIK
Ahmet Hakan UYANIK el 10 de Mayo de 2021
Editada: Walter Roberson el 10 de Mayo de 2021
it is giving similar results as I did actually, what I do is;
T = datetime(1992,1,1) + seconds(gtime);
T.Format = 'yyyy-MM-dd HH:mm:ss';
dy = decyear(T)
both are correct, I guess :) Thank you in advance
Walter Roberson
Walter Roberson el 10 de Mayo de 2021
decyear() appears to require the Areospace Toolbox.
Also, setting the Format is not required for decyear()
Will
Will el 18 de Nov. de 2024
Editada: Will el 18 de Nov. de 2024
This won't match decyear() as (t3-t2) is not the exact length of the year. decyear() calculates the fractional year as (t1-t2)/(number of hours in year or leap year).
Without the aerospace toolbox you can use:
t3 = t2 + calyears(1);
fy = year(t1) + (t1-t2)./(t3-t2)
or with dateshift(), shift to the equivalent time in the year before or after to get the correct length duration, e.g.
t3 = dateshift(t1, 'end', 'year')
t4 = dateshift(datetime(year(t1)-1,1,1), 'end' ,'year');
fy = year(t1) + (t1-t2)./(t3-t4)

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