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How to assign a row matrix to another row matrix

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Andrea Sbaragli
Andrea Sbaragli el 11 de Mayo de 2021
Comentada: Andrea Sbaragli el 11 de Mayo de 2021
This is my function:
function [T1,T2, T3] = dispatch(A)
T1 = zeros(size(A));
T2 = zeros(size(A));
T3 = zeros(size(A));
i=1;
j=1;
k=1;
z=1;
for i=1:height(A)
s=1;
if A {i,2}== 1; % tagID=1
for s=1:4
T1 (j,s) = (A(i,s));
s=s+1
end
j= j+1;
end
if A{i,2}== 2; % tagID=2
for s=1:4
T2(k,s) = A(i,s);
s=s+1
end
k= k+1;
end
if A{i,2}== 3; % tagID=3
for s=1:4
T3(z,s) = (A(i,s));
s=s+1
end
z= z+1;
end
i = i+1;
end
end
it returns me that error:
The following error occurred converting from table to double:
Undefined function 'double' for input arguments of type 'table'. To convert to numeric, use the TABLE2ARRAY function, or extract data using dot or brace subscripting.

Respuestas (1)

Jan
Jan el 11 de Mayo de 2021
Editada: Jan el 11 de Mayo de 2021
The error message suggests:
To convert to numeric, use the TABLE2ARRAY function
Did you try this already?
In one line you write:
if A {i,2}== 1
So you decided to use the brace indexing. Then you write:
T1 (j,s) = (A(i,s))
Now you try to use the parentheses. Why?
  1 comentario
Andrea Sbaragli
Andrea Sbaragli el 11 de Mayo de 2021
if A {i,2}== 1 here I used these brackets because == was not supported otherwise
T1 (j,s) = (A(i,s)) here brace index returns me the same error.
Yes I have already use table2array function but it does not work.
It is strange because inside A all values are in double format..

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