Generate random coordinates around a circle
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How can I generate 15 random 2-D coordinates around a circle of radius R with the center of the circle being a defined [x y] 2-D coordinate? Thanks
4 comentarios
Cedric
el 31 de Jul. de 2013
What have you tried so far?
John
el 31 de Jul. de 2013
Richard Brown
el 31 de Jul. de 2013
Hint: polar coordinates
John
el 31 de Jul. de 2013
Respuestas (2)
Azzi Abdelmalek
el 31 de Jul. de 2013
Editada: Azzi Abdelmalek
el 1 de Ag. de 2013
x0=10; % x0 an y0 center coordinates
y0=20;
radius=10; % radius
angle=-pi:0.1:pi;
angl=angle(randperm(numel(angle),15));
r=rand(1,15)*radius;
x=r.*cos(angl)+x0;
y=r.*sin(angl)+y0;
xc=radius.*cos(angle)+x0;
yc=radius.*sin(angle)+y0;
scatter(xc,yc,'.r')
hold on
scatter(x,y)
xlim([-radius radius]+x0)
ylim([-radius radius]+y0)
axis square
hold off
2 comentarios
Richard Brown
el 1 de Ag. de 2013
Editada: Richard Brown
el 1 de Ag. de 2013
Again, you're choosing from an artificially finite set (63) of evenly spaced angles there. Also, this method will cluster points near the centre of the circle.
John
el 1 de Ag. de 2013
Azzi Abdelmalek
el 31 de Jul. de 2013
Editada: Azzi Abdelmalek
el 31 de Jul. de 2013
x0=10; % x0 and y0 are center coordinates
y0=20;
r=1; % radius
angle=-pi:0.1:pi;
angl=angle(randi(numel(angle),15,1))
x=r*cos(angl)+x0
y=r*sin(angl)+y0
scatter(x,y)
xlim([-r r]+x0)
ylim([-r r]+y0)
axis square
5 comentarios
Richard Brown
el 31 de Jul. de 2013
I presume you mean
angl = 2*pi*rand(1, 15)
John
el 31 de Jul. de 2013
Richard Brown
el 31 de Jul. de 2013
Editada: Richard Brown
el 31 de Jul. de 2013
I seem to recall Roger Stafford answering this very question maybe yesterday? Could be worth trawling through recent questions to have a look. edit Actually, it was a while ago, but it got updated yesterday:
Azzi Abdelmalek
el 31 de Jul. de 2013
Do you mean inside the circle?
Azzi Abdelmalek
el 31 de Jul. de 2013
Richard, I think it's better to use randperm, with rand or randi there is a risk to have repetition
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