Why sym2poly function converts a random string to s polynomial?
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Why sym2poly function converts a random string ('cacssd' for example) to [1 0] polynomial?
syms s
rt='cacd';
num=sym(rt);
snum=sym2poly(num)
I want to handle an error for this but unfortunatly there is no error. Any idea?
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Paulo Silva
el 29 de Mayo de 2011
1 voto
The result [1 0] means that there's a symbolic variable with 1 for it's coefficient, the polynomial is:
1*cacd+0
6 comentarios
sadel
el 29 de Mayo de 2011
Paulo Silva
el 29 de Mayo de 2011
that's a wrong assumption, syms s just defines s as symbolic, the next lines of code have nothing to do with the first, in the third line you define the string inside the variable rt as symbolic and store it in the variable num, it's the symbolic variable num contents that are converted.
Oleg Komarov
el 29 de Mayo de 2011
Yes but you declare sym(rt) which is sym('cacd')
sadel
el 29 de Mayo de 2011
Paulo Silva
el 30 de Mayo de 2011
symvar
ismember
Walter Roberson
el 30 de Mayo de 2011
casd *does* have "the type of a polynomial", just as much as 1*x+0 does.
Perhaps what you want is to restrict to certain variables and then use coeff() or coeffs() to detect whether those variables occur.
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