random number generation for known sum
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harley
el 27 de Ag. de 2013
Comentada: Tejas
el 14 de Jul. de 2020
i what do generate some 15 random numbers that sum for each separate value of say, 60 , 70, 40, 65. How would i go abouts this?
sum = [60 70 40 65];
n=15;
b = [ ];
for i = 1:1:n,
a = randi([1,??]);
b = [b a];
end
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Azzi Abdelmalek
el 27 de Ag. de 2013
n=60;
m=1:n;
a=m(sort(randperm(60,15)));
b=diff(a);
b(end+1)=60-sum(b)
sum(b)
13 comentarios
Bruno Luong
el 13 de Jul. de 2020
Editada: Bruno Luong
el 13 de Jul. de 2020
The easiest way is perhaps using Roger FEX function, then do some sort of "integering" the float solution
sumatarget = 60
n = 15;
ub = 7;
x = floor([0; cumsum(randfixedsum(n,1,sumatarget,0,ub))]);
x(end) = sumatarget; % prevent floating point error
r = diff(x)
The distribution might be not perfectly uniform but possibly close enough and suitable for what ever you want to do with it.
Tejas
el 14 de Jul. de 2020
Integering the solution from Roger's function works very well for me. I do not require the numbers to be perfectly uniform. Thanks!
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