defining a function output properly

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Hi guys! I have a problem in properly defining my output in a function.
According to n= max(position{:,4}); I have different T1, T2,..Tn as arrays.
But how to define all of these in my function output if I do not know in advance how many of them I will have?
[T,n] = paramdisp(position)
Doing so it does not work.
Thanks. I'm new to matlab.

Accepted Answer

Steven Lord
Steven Lord on 17 Jun 2021
So you want to call a function that can return different numbers of outputs and you want to get a number of outputs that is only known when the code is run not when it is written?
Can you define variables with numbered names like X1, X2, X3, ... ? Yes.
Instead I recommend building a cell array and using a comma-separated list.
% Sample data
A = magic(5);
% Preallocate the cell to hold the desired number of outputs
numOutputs = 2;
theOutputs = cell(1, numOutputs);
% Fill in the cell
[theOutputs{:}] = svd(A);
% Call the function with the same number of outputs specified explicitly
% when the code is written so we can compare to the comma-separed list
[output1, output2] = svd(A);
% Compare the two approaches
isequal(theOutputs{1}, output1)
ans = logical
isequal(theOutputs{2}, output2)
ans = logical
If you wanted to call svd with three outputs using the theOutputs cell array the only thing you'd need to change is the line that defines the numOutputs variable.
Stephen23 on 17 Jun 2021
Edited: Stephen23 on 17 Jun 2021
" it possible to use the same approach with arrays?"
A cell array already contains arrays. Every array in a cell of a cell array is itself an array.

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