how to generate cell array based on the size of it.
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jaah navi
el 24 de Jun. de 2021
Respondida: jaah navi
el 15 de Jul. de 2021
My command is B = arrayfun(@(N) randi(2,1,N), repelem((1:3).',5), 'uniform', 0)
when i run it generates B= 15×1 cell array
{[ 2]}
{[ 1]}
{[ 3]}
{[ 3]}
{[ 2]}
{1×2 double}
{1×2 double}
{1×2 double}
{1×2 double}
{1×2 double}
{1×3 double}
{1×3 double}
{1×3 double}
{1×3 double}
{1×3 double}
but the values inside the array are
1
1
2
1
2
[2,1]
[2,1]
[1,2]
[2,2]
[1,1]
[2,2,1]
[1,2,1]
[2,2,2]
[1,1,1]
[2,1,2]
Actually i need to get
1
1
3
1
1
for first 5 rows the value should be 1 as it is 1x1 double
[1,2]
[2,1]
[3,2]
[3,2]
[2,1]
for the next 5 rows the values should be 1,2 and not more than 2, and should not have 2 by leaving 1
[1,2,1]
[3,1,3]
[2,3,3]
[1,2,2]
[3,3,1]
for the next 5 rows the values should not have 3 by leaving 2 and should not have 2 by leaving 1.
Could anyone please help me with this.
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Respuesta aceptada
Mohammad Sami
el 24 de Jun. de 2021
I am bit confused what you mean by should not have 3 by leaving 2 and should not have 2 by leaving 1.
I assume you just want the numbers in order 1,2,3.
B = arrayfun(@(N) colon(1,N), repelem((1:3).',5), 'UniformOutput', false)
11 comentarios
Mohammad Sami
el 6 de Jul. de 2021
You can simply generate A or another variable. Then you can use randperm to sample A to get B. For example if you have an array of 20 values and you want to choose 10, you can do like this.
if true
A = 1:2:40;
B = A(randperm(20,10));
end
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