How to read elements of a matrix diagonally in MATLAB?

Suppose A is a 3X3 matrix

A=[2,5,7; 3,0,1; 9,17,23]

I want to read the elements in this fashion.

2

5 3

9 0 7

1 17

23

Answer 1

[Andrei Bobrov]

A=[2,5,7; 3,0,1; 9,17,23]
k = spdiags(rot90(A));
s = size(k);
nns = nan(s);
ptr = tril(triu(ones(s)),s(1)-1);
nns(ptr>0) = k(ptr>0);
nns(:,1:2:end) = nns(end:-1:1,1:2:end);
out = sort(ptr,'descend');
out(out>0) = nns(~isnan(nns));
out = out';

or

A=[2,5,7; 3,0,1; 9,17,23];

ds = spdiags(rot90(A));
l = spdiags(ones(size(A)));
ds(:,1:2:end) = flipud(ds(:,1:2:end));
l(:,1:2:end) = flipud(l(:,1:2:end));
l2 = sort(l,'descend');
l2(l2>0) = ds(l>0);
out = l2';

[Febin Benjamin]

Thanx Andrei! It worked! And what if I had to read the same matrix as shown below?

7

5 1

23 0 2

3 17

9

[Jan]

@Andrei: I'm impressed. After reading the question I do not have the faintest idea what "reading a matrix in a specific fashion" could mean and what the shown list of value is.

[Febin Benjamin]

@Jan: I tried hard to frame the question in a comprehensive way but that's what I managed to come up with. :) Fortunately, Andrei got it! hehe :)

[Andrei Bobrov]

B = [2,5,7; 3,0,1; 9,17,23];
A = fliplr(B); % and etc