How to reshape 3D matrix ?

I have a 3D matrix of 36*42*7 dimension. I want to reshape it in such a way that I extract two colums from each third dimension. That means my final matrix dimension would be 7*2*756. How can I do this?
For example, Assume I have 4*4*3 matrix
A1= [a b c d; e f g h; i j k l; m n o p]
A2= [q r s t; u v w x; y z A B; C D E F]
A3= [G H I J; K L M N; O P Q R; S T U V ]
Now I want to reshape it to 3*2*8 such that
B1= [a b; q r; G H]
B2=[c d; s t; I J]
B3=[e f; u v; K L]
B4..... B8

2 comentarios

Your question is ambiguous. There are a number of ways 10584 elements can be reshaped from one array to another with the same number of elements. If one assumes that everything should be columnwise, then you can just use reshape()
A = rand(36,42,7);
B = reshape(A,7,2,756);
size(B)
ans = 1×3
7 2 756
Otherwise, you'll have to explain how you want the data to be oriented.
SojM
SojM el 22 de Jul. de 2021
I have edited the question with example.

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 Respuesta aceptada

Stephen23
Stephen23 el 22 de Jul. de 2021
A = randi(9,4,4,3)
A =
A(:,:,1) = 5 7 6 6 7 8 8 1 7 3 8 7 5 1 5 4 A(:,:,2) = 5 6 2 4 2 9 6 2 3 3 2 2 5 1 5 6 A(:,:,3) = 6 9 8 5 1 7 7 9 5 8 5 3 6 5 5 9
B = permute(reshape(permute(A,[2,1,3]),[2,8,3]),[3,1,2])
B =
B(:,:,1) = 5 7 5 6 6 9 B(:,:,2) = 6 6 2 4 8 5 B(:,:,3) = 7 8 2 9 1 7 B(:,:,4) = 8 1 6 2 7 9 B(:,:,5) = 7 3 3 3 5 8 B(:,:,6) = 8 7 2 2 5 3 B(:,:,7) = 5 1 5 1 6 5 B(:,:,8) = 5 4 5 6 5 9

3 comentarios

SojM
SojM el 22 de Jul. de 2021
How can it be done for large matrix of 36*42*7?
Stephen23
Stephen23 el 22 de Jul. de 2021
"How can it be done for large matrix of 36*42*7 to reshpae it into 7*2*756 in a simlar way?"
B = permute(reshape(permute(A,[2,1,3]),[2,756,7]),[3,1,2])
% ^ ^^^ ^
SojM
SojM el 22 de Jul. de 2021
Thanks! It works

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Más respuestas (1)

Chunru
Chunru el 22 de Jul. de 2021
% Generate data (using number 1,...48 to represent a,...V)
Z = permute(reshape(1:48, [4 4 3]), [2 1 3])
Z =
Z(:,:,1) = 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 Z(:,:,2) = 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 Z(:,:,3) = 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48
% First permute the dimension so that a,b,c,.. are along the 1st dim
Z1 = permute(Z, [2 1 3])
Z1 =
Z1(:,:,1) = 1 5 9 13 2 6 10 14 3 7 11 15 4 8 12 16 Z1(:,:,2) = 17 21 25 29 18 22 26 30 19 23 27 31 20 24 28 32 Z1(:,:,3) = 33 37 41 45 34 38 42 46 35 39 43 47 36 40 44 48
% No reshape
Z2 = reshape(Z1, [2 8 3])
Z2 =
Z2(:,:,1) = 1 3 5 7 9 11 13 15 2 4 6 8 10 12 14 16 Z2(:,:,2) = 17 19 21 23 25 27 29 31 18 20 22 24 26 28 30 32 Z2(:,:,3) = 33 35 37 39 41 43 45 47 34 36 38 40 42 44 46 48
% permute
Z3 = permute(Z2, [3 1 2])
Z3 =
Z3(:,:,1) = 1 2 17 18 33 34 Z3(:,:,2) = 3 4 19 20 35 36 Z3(:,:,3) = 5 6 21 22 37 38 Z3(:,:,4) = 7 8 23 24 39 40 Z3(:,:,5) = 9 10 25 26 41 42 Z3(:,:,6) = 11 12 27 28 43 44 Z3(:,:,7) = 13 14 29 30 45 46 Z3(:,:,8) = 15 16 31 32 47 48

3 comentarios

SojM
SojM el 22 de Jul. de 2021
How can it be done for large matrix of 36*42*7 to reshpae it into 7*2*756 in a simlar way?
Chunru
Chunru el 22 de Jul. de 2021
Exactly same:
Z = rand(36, 42, 7);
Z1 = permute(Z, [2 1 3]);
Z2 = reshape(Z1, [2 756 7]); %2x756 = 36*42
Z3 = permute(Z2, [3 1 2]);
Or you can combine the three statements in on as in @Stephen Cobeldick's answer.
SojM
SojM el 22 de Jul. de 2021
Thanks. It worked.

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