Filtering a table with datatime on dates

62 visualizaciones (últimos 30 días)
Niels Hawinkel
Niels Hawinkel el 28 de Jul. de 2021
Respondida: Scott MacKenzie el 28 de Jul. de 2021
I have a table(=tmp) with column 2 (=Var2) consisting of Datetimes (Year-Month-Day-HH-MI-S). There are multiple days in this column and I want to filter out 1 day (i.e. 2019-10-01). I have tried the following:
Filter = tmp(tmp.Var2==datetime(2019,10,1,:,:,:),:);
I get the following error:
Unrecognized function or variable 'datetime'.
I have also tried the following:
Filter = tmp(tmp.Var2==datetime(2019,10,1),:);
which results in an empty table.
Anybody knows what to do?
Thank you in advance.

Respuesta aceptada

Cris LaPierre
Cris LaPierre el 28 de Jul. de 2021
Editada: Cris LaPierre el 28 de Jul. de 2021
In the first case, you are not using correct syntax for MATLAB's datetime function (it doesn't accept colons), so MATLAB is assuming you must have your own function or variable that does, but it can't find it.
In the second case, the == is looking for an exact match (when you don't specify time, midnight is used). None of your datetimes is an exact match.
If you are not looking for an exact match, use conditional statements instead of ==.
rmvDate = tmp.Var2 >= datetime(12019,10,1,0,0,0) & tmp.Var2 < datetime(12019,10,2,0,0,0);
Filter = tmp(rmvDate,:);

Más respuestas (2)

Rik
Rik el 28 de Jul. de 2021
There is probably a native way to do this, but you could also do it yourself:
ref=datetime(2019,10,1);
L=day(ref)==day(tmp.Var2) & month(ref)==month(tmp.Var2) & year(ref)==year(tmp.Var2);
Filter = tmp(L,:);

Scott MacKenzie
Scott MacKenzie el 28 de Jul. de 2021
To remove rows corresponding to 2019-10-01, this should work:
d = datetime(2019,10,01);
removeLogical = isbetween(tmp.Var2, d, d+1);
tmp(removeLogical,:) = [];

Categorías

Más información sobre Matched Filter and Ambiguity Function en Help Center y File Exchange.

Etiquetas

Productos


Versión

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by