How to generate a binary matrix with unique rows (or) columns?

n = 15; k = 10;

flag = 0;
for l=1:2^k

    while(1)
        temp = randi([0,1] , 1,n);
        for m=1:l-1
            if(codeword(m,:) == temp)
                flag = 1;
            end
        end
        if(flag ==0)
            break;
        end
    end
    codeword(l,:) = temp;
end

This is a very time complex code!!

Can anyone suggest any other way with which I can solve this problem?

Thanks.

[Jonas]

i suggest you just write ascending numbers in binary format, then all rows or columns are unique. think about how many rows and digits you need. this way you could produce e.g.

0 0 0 0 0
0 0 0 0 1
0 0 0 1 0
...

the minimum width of your matrix is then given by nextpow2 of your number of rows, but if you need a broader matrix you are free to just use more bits

Answer 1

[Matt J]

Something like this, perhaps?

n = 15; k = 10;

dec2bin( randperm(2^n,k) ) -'0'

ans = 10×15

1 0 1 0 1 0 0 1 1 1 1 0 0 0 0 1 0 0 1 1 0 0 0 1 0 0 1 0 1 0 1 1 0 1 1 1 0 0 1 1 1 0 1 0 0 0 1 1 1 1 0 0 0 0 1 0 1 1 0 0 0 1 0 0 1 1 0 0 0 1 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 1 1 0 1 1 1 0 1 1 1 1 0 1 1 1 0 0 1 1 0 1 1 1 1 1 0 0 1 1 1 1 1 0 1 1 1 0 1 1 0 1 1 0 0 1 1 1 1 1 0 0 1 1 0 1 1 0 1 1 1 1 0 0 1