How to plot function with discontinous range
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Nikhil
el 4 de Oct. de 2013
Comentada: Nikhil
el 4 de Oct. de 2013
Hey, I want to plot P(x) over x=-10:0.5:20
P(x) is defined as
P(x)= x for 0=<x=<1;
= 2-x for 1<=x<=2;
P(x) is zero at other points.
For this I have written following code:
dx=1; xx=1:dx:20;
for i=1:1:20;
fp(1,i)=bilinear(i);
end
plot(xx',fp');
function [ z ] = bilinear( x )
if (1>=x>=0)
z=x;
elseif (2>=x>=1)
z=2-x;
else
z=0;
end
end
But after running this code, I am not getting the triangular plot which I want. Can somebody tell me where is my logic wrong?
Thanks in advance,
Nikhil
0 comentarios
Respuesta aceptada
Walter Roberson
el 4 de Oct. de 2013
1>=x>=0 does not do a range comparison in MATLAB. Instead it tests ((l>=x)>=0) . The l>=x subexpression will return true (1) or false (0) . Both 0 and 1 are >= 0, so the outer comparison will always return true.
Use 0 <= x & x <= 1
And after you have done the assignment, read up on logical indexing.
Más respuestas (0)
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!