a loop that checks for missing decimals in a vector, but it only runs once

if want it to remove the numbers if it doesnt have 1.1, 1.2, 1.3 and so on up til 5 but it only runs once

v = [1.3, 2.2, 2.3, 4.2, 5.1, 3.2, 5.3, 3.3, 2.1, 1.1, 5.2, 3.1];

c = [1.1, 1.2, 1.3 ];
y = find(ismember(v,c));
length(y)
for i = length(v)
    c = [1.1, 1.2, 1.3 ];
    y = find(ismember(v,c));
    length(y)
    if length(y) < 3
        v(y)=[];
        c = c+1;
    else
    c = c+1;
    end
end

[Rik]

What are you actually trying to do? Your code is uncommented and your single line description is not clear to me.

Answer 1

[Awais Saeed]

I think you want to delete elemetns of vector c from vector v. If that is what you want then you can do it as shown below

v = [1.3, 2.2, 2.3, 4.2, 5.1, 3.2, 5.3, 3.3, 2.1, 1.1, 5.2, 3.1];
c = [1.1, 1.2, 1.3 ];

y = find(ismember(v,c));

for col = length(y):-1:1    % You must do this in reverse order as the size of vector v will keep changing
	idx = y(col);
	v(idx) = [];
end

[Rik]

If that is the goal you can do it in one go:

v = [1.3, 2.2, 2.3, 4.2, 5.1, 3.2, 5.3, 3.3, 2.1, 1.1, 5.2, 3.1];
c = [1.1, 1.2, 1.3 ];
L=ismember(v,c);
v(L)=[]

v = 1×10

2.2000 2.3000 4.2000 5.1000 3.2000 5.3000 3.3000 2.1000 5.2000 3.1000

[Mads Albertsen]

i figured it out, was just missing i = 1:length(v) since i need c to check for all the numbers uptil 5, so 4.2 also is removed since it is missing 4.1 and/or 4.3, sorry for being unclear