Problem 3095. Return fibonacci sequence do not use loop and condition version 2

Solution 599135

Submitted on 20 Mar 2015 by LY Cao

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Rafael S.T. Vieira on 31 Aug 2020

I won't judge because a lookup table is really tempting when the problem author adds a plethora of restrictions.

Test	Status	Code Input and Output
1	Pass	%%% Clean workspace % !/bin/cp fib.m safe % !/bin/rm . % !/bin/mv safe fib.m % Clean user's function from some known jailbreaking mechanisms functions={'!','feval','eval','str2func','str2num','regex','system','dos','unix','perl','assert','fopen','write','save','setenv','path','please','for','if','while','switch','round','roundn','fix','ceil','char','floor','\.','^','power'}; fid = fopen('fib.m'); st = char(fread(fid)'); for n = 1:numel(functions) st = regexprep(st, functions{n}, 'error(''No fancy functions!''); %','ignorecase'); end st = regexprep(st, 'function', 'error(''No fancy functions!''); %','ignorecase',2); fclose(fid); fid = fopen('fib.m' , 'w'); fwrite(fid,st); fclose(fid);
2	Pass	%% n = 1:5; f = [1 1 2 3 5]; assert(isequal(fib(n),f))
3	Pass	%% n = 7 : 10; f = [13 21 34 55]; assert(isequal(fib(n),f))
4	Pass	%% n = 20 : 22; f = [ 6765 10946 17711]; assert(isequal(fib(n),f))

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