Problem 43667. Use a timetable to analyze a train timetable (Part 4)

Created by Heather Gorr, PhD

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You are analyzing a train timetable (you have some time to kill since you just missed your train!) What is the average daily trip duration?
Example:
DepTime = datetime(2016,11,1,[6 8 9],[22 51 05],0)';
ArrTime = datetime(2016,11,1,[9 10 12],[17 32 09],0)';
Destination = categorical({'BOS';'NYC';'BOS'});
tt = timetable(DepTime,Destination,ArrTime)
tt = 
     DepTime          Destination          ArrTime       
____________________    ___________    ____________________
01-Nov-2016 06:22:00    BOS            01-Nov-2016 09:17:00
01-Nov-2016 08:51:00    NYC            01-Nov-2016 10:32:00
01-Nov-2016 09:05:00    BOS            01-Nov-2016 12:09:00
The result should be a duration variable:
Dur = [duration(3,9,05);duration(2,55,15);duration(3,0,24)]
Dur = 
3×1 duration array
 03:09:50
 02:55:15
 03:00:24
Feature Tip: R2016b introduces timetables with related functions which may be helpful. To learn more see MATLAB Timetables.
Related Problems:
Use a timetable to analyze a train timetable (Part 1)
Use a timetable to analyze a train timetable (Part 2)
Use a timetable to analyze a train timetable (Part 3)
Use a timetable to analyze a train timetable (Part 4)
Use a timetable to analyze a train timetable (Part 5)

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Last Solution submitted on Jan 14, 2026

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Peng Liu on 22 Nov 2016

Could you be more specific on the underlying relationship between the input (timetable) and output (mean duration)? That is, among which group are you calculating the mean duration? From your example, there are only 2 groups of destinations, i.e., BOS and NYC, but why there are 3 values in the output? What's the mapping behind? Also, your problems including Part 1, 4, 5 are all based on single test, which allows hard-coded solution to lead.

Nikolaos Nikolaou on 28 Oct 2019

Peng do share the grouping method cause it eludes me :)

Rafael S.T. Vieira on 30 Aug 2020

There seems to be an error with the test suite: the first mean time should be 03:09:50 and not 03:09:05. And the test code should probably be abs(ttDur - Dur) <= duration([0 0 1]) (not 0.01).

goc3 on 22 Apr 2022

The test suite has been updated to use 03:09:50. Also, the check for each of the three average durations is made against 0.0001 now, instead of 0.01, to ensure 03:09:05 will not pass (as that was incorrect). Finally, the test suite now accommodates a row vector (in addition to the expected column vector) as the function output.

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Problem 43667. Use a timetable to analyze a train timetable (Part 4)

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