photo

RobF


Con actividad desde 2018

Followers: 0   Following: 0

Mensaje

Student @ TU Munich

Estadística

All
  • Revival Level 1
  • Knowledgeable Level 1
  • First Answer
  • Solver

Ver insignias

Feeds

Ver por

Respondida
App Designer: How to open a second GUI or a new window with panels, lamps, edit fields, etc. by a ButtonPush callback ?
Have you tried to create a button, its callback and modify the callback? You could try fig = figure(); assignin('base',...

casi 6 años hace | 0

Respondida
Problem with mean function
Two commands that might always help when having path issues are the following: >> restoredefaultpath and >> rehash ...

alrededor de 6 años hace | 1

Respondida
How to give discrete input from workspace to simulink?
Hello Anirudh, it seems like your time vector is empty. To be able to use data from your workspace in Simulink, one soluti...

más de 6 años hace | 0

Respondida
How to change structure fields from 1 x Y double to Y x 1 double (Horizontal;1 row,Y columns to Vertical;1 column,Y rows)
Maybe a little change to your code will do the job (just transpose the imported arrays): SP1OCVT00 = struct('Test_time',[ra...

más de 6 años hace | 1

| aceptada

Respondida
How to extract RGB
Extraction of RGB values: C = imread('ngc6543a.jpg'); % Sample image file % Coordinates of point/pixel P1: x1, y1 x1 ...

más de 6 años hace | 0

Respondida
How to turn off automatic logging of simulation run signals in data inspector in 2017b.
This might help: <https://www.mathworks.com/matlabcentral/answers/158026-can-we-control-data-inspector-from-command-line?s_ti...

más de 6 años hace | 0

Respondida
How can I plot in the same coordinate system this two images that the execution of the two codes below gives?
You might want to delete/comment out the hold off statement and try the following: % circle(1, 2, 3) x=1; y=2; r=3...

más de 6 años hace | 0

Respondida
I have got a set of data; one column is for wind(mph) another column one is for temperature(in Fahrenheit). using the wind chill factor formula i want to find out the WCF for each tempetaure and wind
This should do the job: WCF = 35.7 + 0.6.*T - 35.7.*(V.^0.16) + 0.43.*T.*V.^0.16 where V in mph and T in deg Fahrenheit....

más de 6 años hace | 1