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extruct non zeros values and put into a short matrics
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A =
0 0 0 0 5 0 0 8 0 0 0 0 8
0 0 0 5 0 0 0 8 0 0 0 0 9
0 0 0 5 0 0 0 7 0 0 0 0 8
0 0 0 0 5 0 0 0 8 0 0 0 9
0 0 0 6 0 0 0 8 0 0 0 0 9
0 0 0 5 0 0 0 7 0 0 0 0 8
0 0 0 8 0 0 0 8 0 0 0 0 9
I want to extruch a small matrics (with 3 columns) containing only non zeros values
Results:
5 8 8
5 8 9
5 7 8
5 8 9
6 8 9
5 7 8
8 8 9
ho I can do this smartly?
thanks
1 comentario
Image Analyst
el 18 de Nov. de 2013
To do it smartly and robustly, you'd check to make sure that there are the same number of zeros in each row. If there aren't you'd need to decide how to handle that, for example, take the first or last three
threeValues = find(oneRow~= 0, 3, 'first'); % Could be empty, 1, 2, or 3 at most.
if length(threeValues) == 3 .... etc.
Respuestas (1)
Azzi Abdelmalek
el 18 de Nov. de 2013
Editada: Azzi Abdelmalek
el 18 de Nov. de 2013
out=cell2mat(arrayfun(@(x) A(x,A(x,:)~=0),(1:size(A,1))','un',0))
%or
n=size(A,1);
B=zeros(n,3);
for k=1:n
B(k,:)=A(k,A(k,:)~=0);
end
B
2 comentarios
The Matlab Spot
el 18 de Nov. de 2013
this is good...
out=cell2mat(arrayfun(@(x) A(x,A(x,:)~=0),(1:size(A,1))','un',0))
Azzi Abdelmalek
el 18 de Nov. de 2013
Not necessary, the second using for loop is slightly faster then arrayfun
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