# I have x and y data, How can I do linear fit to the data, find out c of linear fit line and slope with respect to y=m*x ?

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RS el 8 de Dic. de 2013
Comentada: Image Analyst el 15 de Dic. de 2013
I have x and y data, How can I do linear fit to the data, find out c of linear fit line and slope with respect to y=m*x ?
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### Respuestas (2)

Image Analyst el 8 de Dic. de 2013
Editada: Image Analyst el 8 de Dic. de 2013
See my demo. The main lines to focus on are
linearCoefficients = polyfit(x, y, 1)
yFit = polyval(linearCoefficients, xFit);
Here's the demo.
% Demo to illustrate how to use the polyfit routine to fit data to a polynomial
% and to use polyval() to get estimated (fitted) data from the coefficients that polyfit() returns.
% Demo first uses a linear fit, then uses a cubic fit.
% Initialization steps.
clc; % Clear the command window.
close all; % Close all figures (except those of imtool.)
clear; % Erase all existing variables. Or clearvars if you want.
workspace; % Make sure the workspace panel is showing.
format long g;
format compact;
fontSize = 20;
%============= LINEAR FIT ===================================
x = linspace(-10, 10, 20); % Make 20 samples along the x axis
% Linear relation, with noise
slope = 1.5;
intercept = -1;
noiseAmplitude = 15;
y = slope .* x + intercept + noiseAmplitude * rand(1, length(x));
% Plot the training set of data.
subplot(2, 1, 1);
plot(x, y, 'ro', 'MarkerSize', 8, 'LineWidth', 2);
grid on;
xlabel('X', 'FontSize', fontSize);
ylabel('Y', 'FontSize', fontSize);
title('Linear Fit', 'FontSize', fontSize);
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0 1 1]);
% Give a name to the title bar.
set(gcf, 'Name', 'Demo by ImageAnalyst', 'NumberTitle', 'Off')
% Do the regression with polyfit
linearCoefficients = polyfit(x, y, 1)
% The x coefficient, slope, is coefficients(1).
% The constant, the intercept, is coefficients(2).
% Make fit. It does NOT need to have the same
% number of elements as your training set,
% or the same range, though it could if you want.
% Make 300 fitted samples going from -15 to +20.
xFit = linspace(-15, 20, 500);
% Get the estimated values with polyval()
yFit = polyval(linearCoefficients, xFit);
% Plot the fit
hold on;
plot(xFit, yFit, 'b', 'LineWidth', 2);
legend('Training Set', 'Fit', 'Location', 'Northwest');
%============= CUBIC FIT ===================================
x = linspace(-10, 10, 20); % Make 20 samples along the x axis
% Cubic relation, with noise
c1 = 1;
c2 = 2;
c3 = -10;
c4 = 4;
noiseAmplitude = 500;
y = c1 .* x .^3 + c2 .* x .^2 + c3 .* x + c4 + noiseAmplitude * rand(1, length(x));
% Plot the training set of data.
subplot(2, 1, 2);
plot(x, y, 'ro', 'MarkerSize', 8, 'LineWidth', 2);
grid on;
xlabel('X', 'FontSize', fontSize);
ylabel('Y', 'FontSize', fontSize);
title('Cubic Fit', 'FontSize', fontSize);
% Do the regression with polyfit
cubicCefficients = polyfit(x, y, 3)
% The x coefficient, slope, is coefficients(1).
% The constant, the intercept, is coefficients(2).
% Make fit. It does NOT need to have the same
% number of elements as your training set,
% or the same range, though it could if you want.
% Make 300 fitted samples going from -13 to +12.
xFit = linspace(-13, 12, 500);
% Get the estimated values with polyval()
yFit = polyval(cubicCefficients, xFit);
% Plot the fit
hold on;
plot(xFit, yFit, 'b', 'LineWidth', 2);
grid on;
legend('Training Set', 'Fit', 'Location', 'Northwest');
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Image Analyst el 15 de Dic. de 2013
S, are you still alive?

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sixwwwwww el 8 de Dic. de 2013
If you are given values of x and y and both x and y hase same number of elements in them then you can compute m and c as follow:
fitvars = polyfit(x, y, 1);
m = fitvars(1);
c = fitvars(2);
If you don't have linear line then you can use higher values then 1 in the first line of code. I hope it helps. Good luck!
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