non-integer power for a model ?
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I wanna to make a program that generate a CRONE regulation system, and it use fractional power for models and I can't find how to do it
6 comentarios
Amit
el 31 de Dic. de 2013
can you elaborate the problem?
Image Analyst
el 31 de Dic. de 2013
Editada: Image Analyst
el 31 de Dic. de 2013
In the last way, what is "g"? And what is unknown? The P, the x, or the m? I also don't know what tf() is.
Mohamed
el 1 de En. de 2014
Image Analyst
el 1 de En. de 2014
Well g is gone, so that's good. I still don't know what is inside tf() since you didn't give the code for that function. And you still didn't answer my questions. I'm still not sure how to help. If you run your code, but fixed to use .^ instead of ^ you get this:
P=[1 3 6];
m = 1.4; %non integer power
P .^ m% (x²+3x+6)^m;
ans = 1 4.65553672174608 12.2860350664753
There are no unknowns. You have an m, you have a P, you raised P to the m power, end of story. What does this x in the comment have to do with anything???
Mohamed
el 2 de En. de 2014
Respuestas (2)
Image Analyst
el 31 de Dic. de 2013
So you want to have a model like y = a * x .^ n. Do you know the fractional power, n, or is it an unknown? Either way, one way is to take the log of the equation which turns it into a linear equation - that's pretty common and works reasonably well, though I'm not sure if it gives you the absolute minimum sum of residuals as compared to some other non-linear method.
log(y) = log(a) + n * log(x)
yNew = aNew + n * xNew
Now it's a linear equation in the unknowns aNew and n and you can just use least squares.
Image Analyst
el 2 de En. de 2014
You're doing it right. Just assign some x over some range you care about. Then construct P and finally raise it to a power, for every P (every x value) that you have in your array:
x = linspace(3, 25, 50); % Some arbitrary x values that we want.
P = x .^ 2 + 3 * x + 6;
m = 1.4; % non integer power
output = P .^ m;
plot(x, output, 'bo-');
grid on;
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0 1 1]);
Is that what you want?
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