Need help with finding distances in a matrix program
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Sebastian
el 25 de En. de 2014
Comentada: Sebastian
el 25 de En. de 2014
I have an A matrix, in which I need to find the distances between the points. I have the formulas, but I need help to translate this into matlab.
Lets say that a is equal to:
A=
0 1 0 0 1 0
1 0 0 0 0 0
0 0 0 0 1 0
I have a program to create a new matrix called B,finding this points in which the first column is the number of point, the second column is the x coordinate of the point and the third column is the y coordinate. In this case will be:
B=
1 2 1
2 5 1
3 1 2
4 5 3
Here is the code for this program:
clear z
p=1;
[row,col] = size(A);
for i = 1:row
for j=1:col
if(A(i,j)>0)
z(p,:)=[j,i];
p=p+1;
end
end
end
B=[(1:p-1)',z] %B matrix 1 col is #of point, 2 col is xcoord,3 col is ycoord
I need to find the distances between these points, in this case will be dijx(x distance) and dijy (y distance). For this matrix these will be the distances(absolute value from one point to another point):
dijx=
0 3 1 3
3 0 4 0
1 4 0 4
3 0 4 0
dijy=
0 0 1 2
0 0 1 2
1 1 0 1
2 2 1 0
Can you help me to create a for loop code to find those distances? Thank you!!
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Respuesta aceptada
Andrei Bobrov
el 25 de En. de 2014
Editada: Andrei Bobrov
el 25 de En. de 2014
[r,c]=find(A');
dij = dist([r,c]'); % dist from Neural Network Toolbox
or
[r,c]=find(A');
dijx = bsxfun(@minus,r,r');
dijy = bsxfun(@minus,c,c');
dij = hypot(dijx,dijy);
Más respuestas (1)
Image Analyst
el 25 de En. de 2014
You can get B in two lines of code:
[rows, columns] = find(A)
B = [[1:length(rows)]', rows, columns]
Now I'm not sure what distances you are after are you wanting every distance from N points to the other N-1 points? So you'll have every possible pairing and N*(N-1) distance?
3 comentarios
Image Analyst
el 25 de En. de 2014
Well, you can flip the order with
[rows, columns] = find(A')
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