normalization image, normalization distance pixels
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Hello,
i have image

when I use my code:
img = imread('obraz.bmp');
img = rgb2gray(img);
imshow(img);
%%normalization
img = ( img - min(img(:)) ) ./ ( max(img(:)) - min(img(:)) );
img = ~img;
[m n]=size(img)
P = [];
for i=1:m
for j=1:n
if img(i,j)==1
P = [P ; i j];
end
end
end
size(P);
MON=P;
[IDX,ctrs] = kmeans(MON,3);
clusteredImage = zeros(size(img));
clusteredImage(sub2ind(size(img) , P(:,1) , P(:,2)))=IDX;
imshow(label2rgb(clusteredImage))
my output is

as I am to normalize the image? when I want to output as

Thank for you help
Respuestas (2)
Image Analyst
el 1 de Abr. de 2014
Get rid of all that. It's a totally wrong approach. You don't need normalization or building up a list of white pixels. Simply threshold the image and label it and apply colors.
rgbImage = imread('obraz.bmp');
grayImage = rgbImage(:,:,2); % Extract green channel.
binaryImage = grayImage > 128;
labeledImage = bwlabel(binaryImage);
coloredLabels = label2rgb (labeledImage, 'hsv', 'k', 'shuffle'); % pseudo random color labels
imshow(labeledImage, []);
Of course if you like really compact code, the 2nd, 3rd, and 4th lines can be combined into one line.
9 comentarios
Tomas
el 1 de Abr. de 2014
Image Analyst
el 1 de Abr. de 2014
What you say is unclear. Do you want the distance of every single black pixel to every single other black pixel? Or do you want the distance between closest black pixels? If it's the latter, check out bwdist(). I don't see any reason for the former. I also don't know what "normalizing" means in the context you show.
Image Analyst
el 1 de Abr. de 2014
See attached code (in blue below the image) to produce the image below.

Tomas
el 1 de Abr. de 2014
Image Analyst
el 1 de Abr. de 2014
I don't have the stats toolbox so I can't help you. kmeans seems like it would fail quite easily and often so I don't know why you'd use it instead of something that is robust and foolproof.
Tomas
el 1 de Abr. de 2014
Image Analyst
el 1 de Abr. de 2014
Is the shape the white objects or the black objects? Either way, it's trivial with labeling and difficult and faulty with kmeans. If you look at the x,y locations of the points then the centroid of the circle is really close to the centroids of the polygons and the polygon pixels go very near the centroid of the circle and might be classified as circle instead of polygons. Good example of why kmeans is not good for connected components labeling.
Arshad Ali
el 10 de Mayo de 2017
0 votos
Can any one please help me how to normalized pixel area being consumed by each colour. (Normalized area consumed by red colour=No of pixels of Red/( Total no of pixels in the image)
1 comentario
Image Analyst
el 10 de Mayo de 2017
See color segmentation demos. Once you have a binary image that defines what pixels you consider to be "red", you simply divide the sum of true/1/white pixels in it by the number of pixels in the image.
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