Assigning a placeholder variable
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I am by no means a Matlab expert so I apologize if this is a question with an easy answer, but I couldn't find any help online.
I have y=x*exp(-(x^2))+x for all x
y is given by previous functions and is some real number
however,x is not yet defined, and I can't get the formula into x= form How can I input this formula without having x defined yet? Is there a way to define x as an empty value and then impute the formula, getting the actual value for x? What am I missing here?
EDIT: I got it to work using fzero. Now I am trying to rework the code to get it to work when y exists as a range of known values instead of one known value. It looks like fzero can't be vectorized, so I tried using a for loop. I get the results, but r0 gts printed into the command line for each value of rm. I want to create a vector of all of the r0 values (and then all of the x0,y0 values). Is this possible?
Here is the code I currently have:
mu=2
nsamples=100;
for rm=linspace(-2,2,10000)
funct=@(r0,rm)mu*r0.*exp(-r0.^2)+r0-rm
options=optimset('Display','off')
[r0]=fzero(@(r0) funct(r0,rm),-2)
end
3 comentarios
Sara
el 26 de Jun. de 2014
Do you mean that you want to solve for x, given y? fzero can help you with that
Respuestas (2)
your_fun = @(x) x.*exp(-(x.^2) ) + x
your_fun(3)
Please accept the answer that best solves your problem.
3 comentarios
Daniel
el 27 de Jun. de 2014
Image Analyst
el 27 de Jun. de 2014
You forgot to attach your updated code.
Daniel
el 27 de Jun. de 2014
Elias Hasle
el 6 de Nov. de 2018
Couldn't you use the symbolic toolbox? E.g.:
syms x_symbol
y = <some expression of x_symbol>
z = <some other expression of x_symbol, could include the y expression etc.>
x_value = 1234
z_result = double(subs(z, x, x_value))
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