Access data from table and assign to variables

Hi, I am making a program with excel file already converted to table and now I need to code such that when a user gives an input a certain coloumn is taken and then assign certain variables to some particular blocks in that row.
example:
Vehicle speed fuel
Car 50 2
Bike 20 1
Cycle 5 0
Like user gives input as Bike. then I need to assign variables created like speed and fuel to use in further equations.

4 comentarios

Image Analyst
Image Analyst el 27 de Ag. de 2021
What type of variable do you want to create? A new table? Add a row to an existing table? A new instance of a class variable? A new structure, perhaps added onto an existing structure array?
No changes to the table . I want to extract other values like speed and fuel based on the input given by user(eg Bike). and use them for further calculations.
Stephen23
Stephen23 el 27 de Ag. de 2021
"...then I need to assign variables created like speed and fuel to use in further equations."
Why not just access the data directly from the table?
thank you for answering its clear now

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 Respuesta aceptada

Ive J
Ive J el 27 de Ag. de 2021
Editada: Ive J el 27 de Ag. de 2021
This might work
tab = table({'Car'; 'Bike'; 'Cycle'}, [50; 20; 5], [2; 1; 0],...
'VariableNames', {'Vehicle', 'speed', 'fuel'})
tab = 3×3 table
Vehicle speed fuel _________ _____ ____ {'Car' } 50 2 {'Bike' } 20 1 {'Cycle'} 5 0
filterIn = 'Bike'; %input('what to filter? ', 's');
idx = ismember(tab.Vehicle, filterIn);
if ~any(idx)
fprintf('oops, not found!\n')
return
end
dataTable = tab(idx, :);
dataStruct = table2struct(dataTable, 'ToScalar', true);
as table:
disp(dataTable)
Vehicle speed fuel ________ _____ ____ {'Bike'} 20 1
or struct:
disp(dataStruct)
Vehicle: {'Bike'} speed: 20 fuel: 1

2 comentarios

after getting this is there a way we can assign say x = speed i.e x = 20. x is already defined
Thank you for this.
Ive J
Ive J el 27 de Ag. de 2021
Editada: Ive J el 27 de Ag. de 2021
Yes you can easily assign struct fields to variables, but it's better to use structs as they are, it's much easier and more clear!
x = dataStruct.speed; % or other field names, see fieldnames help

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Más respuestas (1)

Picking up from @Ive J's example, but use 'Vehicle' as Row Labels to take advantage of native table indexing:
t = table([50; 20; 5], [2; 1; 0], 'VariableNames', ["speed", "fuel"], 'RowNames', ["Car"; "Bike"; "Cycle"])
t = 3×2 table
speed fuel _____ ____ Car 50 2 Bike 20 1 Cycle 5 0
t("Bike", ["speed", "fuel"]) % or if you want all variables, t("Bike", :)
ans = 1×2 table
speed fuel _____ ____ Bike 20 1

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Preguntada:

el 27 de Ag. de 2021

Respondida:

el 30 de Ag. de 2021

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