Binning returns zero values/column vector of 0's

2 visualizaciones (últimos 30 días)
Zhou Ci
Zhou Ci el 9 de Sept. de 2021
Comentada: Image Analyst el 28 de Sept. de 2021
Hi all,
I have a table containing values from 3 parameters, T, V and P. My assignment says;
-For 1C interval you'll have several pixels fall in this interval.
-Calculate the median R for those pixels within this 1C.
-For this 1K interval, you would have several pixels.
I tried to do this but it returns a column vector of zero. Data is attached. Kindly suggest me how to accomplish it. Thank you.
temperature_rounded=round(Temp,0);
T=unique(temperature_rounded);
Z=NaN(size(T));
%%
for n=1:numel(T)
L= T==T(n); %select all positions where the rounded temperature is a specific value
Z(n)=median(Radius(L));%calculate the median for this selection
end
  1 comentario
Image Analyst
Image Analyst el 28 de Sept. de 2021
Code snippet is attached, but no data. Did you forget to attach it?
Isn't a 1 degree Kelvin interval the same as a 1 degree Celcius interval? So why wouldn't the "number of pixels" be the same for the two?
Have you learned of the functions histogram() and splitapply()?

Iniciar sesión para comentar.

Respuestas (1)

Walter Roberson
Walter Roberson el 9 de Sept. de 2021
Editada: Walter Roberson el 9 de Sept. de 2021
L = temperature_rounded == T(n);

Categorías

Más información sobre Visual Exploration en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by