Question about sorting an array column by column

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helen orins
helen orins el 27 de Sept. de 2021
Comentada: helen orins el 27 de Sept. de 2021
I need to sort each column of a 1073x15 array for a heatmap in MATLAB.
[~,sortdices] = sort(choose_data(:,1),'ascend');
%choose_data = choose_data(:,sortdices);
for i=1:15
choose_data(:,i) = choose_data(sortdices,i)
end
this is my code. choose_data is the 1073x15 array. My output ends up being the first column sorted in ascending order, but the rest not. How do I fix it, such that all columns are sorted in ascending order? (Thank you for any help!)
  2 comentarios
Walter Roberson
Walter Roberson el 27 de Sept. de 2021
Is each column to be sorted independently, or should the columns be sorted "within" each previous column? That is, if two rows have the same value for column 1, then look at column 2 to determine the order; if those are equal, look at column 3, and so on ? If so then sortrows()
helen orins
helen orins el 27 de Sept. de 2021
Each column is sorted independently. So column 1, in ascending order. Done. Next, column 2, and so on. Hence the loop. So that's why I created the function. The rows are untouched.

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Respuestas (2)

the cyclist
the cyclist el 27 de Sept. de 2021
Editada: the cyclist el 27 de Sept. de 2021
choose_data = sort(choose_data)
will sort every column independently. Ascending sorting is the default, so you don't need to specify that. (But it also doesn't hurt, and might make the code clearer.)
  2 comentarios
helen orins
helen orins el 27 de Sept. de 2021
I tried that, but this is the error I got: Unable to perform assignment because the size of the left side is 1073-by-1 and the size of the right side is 16095-by-1.
the cyclist
the cyclist el 27 de Sept. de 2021
Editada: the cyclist el 27 de Sept. de 2021
Strange. Here is an example that illustrates that the syntax works:
M = magic(3)
M = 3×3
8 1 6 3 5 7 4 9 2
M = sort(M)
M = 3×3
3 1 2 4 5 6 8 9 7
Note that you do not need to do anything in a for loop. That one line of code will sort all columns of the array. You also don't need to do any indexing into the array.

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Steven Lord
Steven Lord el 27 de Sept. de 2021
Specify the dim input argument to the sort function.
A = magic(5)
A = 5×5
17 24 1 8 15 23 5 7 14 16 4 6 13 20 22 10 12 19 21 3 11 18 25 2 9
B = sort(A, 1)
B = 5×5
4 5 1 2 3 10 6 7 8 9 11 12 13 14 15 17 18 19 20 16 23 24 25 21 22
% Compare with
C = sort(A, 2)
C = 5×5
1 8 15 17 24 5 7 14 16 23 4 6 13 20 22 3 10 12 19 21 2 9 11 18 25
If you want to sort one of the columns and have the rest of the rows rearrange correspondingly see the sortrows function.
D = sortrows(A, 2) % sort by column 2
D = 5×5
23 5 7 14 16 4 6 13 20 22 10 12 19 21 3 11 18 25 2 9 17 24 1 8 15

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