How to filter out the elevation higher than 0

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Nicholas Deosaran
Nicholas Deosaran el 10 de Oct. de 2021
Comentada: Nicholas Deosaran el 13 de Oct. de 2021
Hello all,
I wrote my code to get the elevation of the Cape Fear Area to make a mesh grid.
I wanted to know if there is a way to filter out any elvation higher than 0.
filename = 'crm_vol2.nc';
meta = ncinfo(filename);
disp('Variable List');
names = {meta.Variables.Name}';
% there are 3 variables inside the netCDF file: x, y, z
x = ncread(filename, 'x');
y = ncread(filename, 'y');
z = ncread(filename, 'z');
z = z';
min_x = min(x);
max_x = max(x);
min_y = min(y);
max_y = max(y);
dxy = 8.3333e-04;
[xv, yv] = meshgrid(min_x:dxy:max_x,min_y:dxy:max_y);
dx = dxy;
dy = dxy;
x_low = -78.22; % longitude low
x_up = -77.30; % longitude up
y_low = 33.82; % latitude low
y_up = 34.33; % latitude up
[xp, yp] = meshgrid(x_low:dx:x_up, y_low:dy:y_up);
zp = interp2(xv, yv, z, xp, yp); % makes the zp array for depth
% export xp, yp, and zp into text file to be imported into MIKE mesh generator!
% for loop to get needed data for xp, yp, and zp
[m,n] = size(xp);
xyz = zeros (m*n,3) ;
count = 0;
for i = 1:m
for j = 1:n
count = count+1;
xyz (count, 1 ) = xp (i,j);
xyz (count, 2 ) = yp (i,j);
xyz (count, 3 ) = zp (i,j);
end
end
xyz = xyz(1:count,:);
save mesgrid.xyz xyz -ascii
This code just takes all the data and put them in coloums and able to save it as an .xyz file.
  2 comentarios
Image Analyst
Image Analyst el 10 de Oct. de 2021
Make it easy for us to help you. Please attach 'crm_vol2.nc'.
Nicholas Deosaran
Nicholas Deosaran el 10 de Oct. de 2021
I would love to attached the 'crm_vol2.nc' file but it is to big to attached even when its zipped and compressed.
is the link i got the infomration from and "download NetCDF File"

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Jan
Jan el 10 de Oct. de 2021
I do not see, where your filter out elevations greator 0.
It is faster to call interp2 with vectors as coordinates. So avoid calling meshgrid but provide the vectors directly.
Replace:
[m,n] = size(xp);
xyz = zeros (m*n,3) ;
count = 0;
for i = 1:m
for j = 1:n
count = count+1;
xyz (count, 1 ) = xp (i,j);
xyz (count, 2 ) = yp (i,j);
xyz (count, 3 ) = zp (i,j);
end
end
by
xyz = [xp(:), yp(:), zp(:)];
  3 comentarios
Walter Roberson
Walter Roberson el 10 de Oct. de 2021
xyz = [xp(:), yp(:), zp(:)];
xyz(xyz(:,3) > 0, :) = [];
Nicholas Deosaran
Nicholas Deosaran el 13 de Oct. de 2021
Thank you!

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