how to convert 1x2 double into two 1x1

Hi I was coding when I had this error:

Time_msg_match = string(Time_msg_match);
Error using string
Conversion from cell failed. Element 61649 must be convertible to a string scalar.
 
>> Time_msg_match(61649)

ans =

  1×1 cell array

    {2×1 double}

How can I concadenate this 2x1 double?

I wrote:

    Time_msg_match1 = num2str(cat(1, Time_msg_match{:}));

But the result is not what I wanted. Thanks in advance

Answer 1

[Image Analyst]

Try this to create 2 separate variables out of that 1x2 cell array

Time_msg_match1 = Time_msg_match{1};
Time_msg_match2 = Time_msg_match{2};

[flashpode]

I was not meant to do that. I wanted:

Time_msg_match is a 311282x1 cell where some of the cells have (2x1 double or 3x1 double). I want them to split¿? in diferent cells so the total number of cells of variable Time_msg_match increase.

[Image Analyst]

Attach Time_msg_match in a .mat file so I can try some things. Come on, make it easy for me to help you, not hard.

[flashpode]

Here it is. Sorry for the delay

[Image Analyst]

@vicente Noguer, that is a cell array of 311,472 rows and one column. Inside each of those cells is a single scalar number. I'm not sure what to do with this since the cells do not contain either a 2x1 or 3x1 double array. Try this:

s = load('Time_msg_match.mat')
Time_msg_match = s.Time_msg_match;
numCells = numel(Time_msg_match)
% Allocate a second array.  Make it a cell array, but it really probably doesn't have to be.
% Time_msg_matchCA = cell(numCells+10000, 1); % More than needed - we'll crop later.
% Allocate a second array.  A double array since we don't need it to be a cell array.
Time_msg_match2 = zeros(numCells+10000, 1); % More than needed - we'll crop later.
vector2Index = 1;
for k = 1 : numCells
    len = length(Time_msg_match{k});
    if len == 1
        Time_msg_match2(vector2Index) = Time_msg_match{k}; % Assign to double array.
        % 		Time_msg_matchCA{vector2Index} = Time_msg_match{k}; % Assign to cell array.
        vector2Index = vector2Index + 1;
    else
        fprintf('Row %d has %d elements in it.\n', k, length(Time_msg_match{k}));
        for k2 = 1 : len
            thisVector = Time_msg_match{k};
            Time_msg_match2(vector2Index) = thisVector(k2);
            % 			Time_msg_matchCA{vector2Index} = thisVector(k2);
            vector2Index = vector2Index + 1;
        end
    end
end
% Crop off unused elements.
if vector2Index < numCells
    Time_msg_match2 = Time_msg_match2(1 : vector2Index - 1);
    % 	Time_msg_matchCA = Time_msg_matchCA(1 : vector2Index - 1);
end
fprintf('Original   Time_msg_match had %d rows.\n', numCells)
fprintf('Afterwards Time_msg_match had %d rows.\n', numel(Time_msg_match2))

I put the results into a double column vector Time_msg_match2. If you really need a cell array, like some other function is expecting a cell array not a double array, then uncomment the lines mentioning Time_msg_matchCA and comment out the ones mentioning Time_msg_match2.

[flashpode]

I did not get what you tried to do but look what I have when I code

>> Time_msg_match = Time_msg_match';
>> Time_msg_match = string(Time_msg_match)
Error using string
Conversion from cell failed. Element 61649 must be convertible to a string scalar.
 
>> Time_msg_match(61649)

ans =

  1×1 cell array

    {2×1 double}

[flashpode]

But I have deleted this line and it has worked so it is resolved. Thank you. Now I want to use this to index a duration array but I am gonna look by myself to do this. Once again thank you!!!!!

Answer 2

[Rik]

It looks like this is what you want:

x=Time_msg_match(61649);
x=x{1};

[flashpode]

But this can be save in the same variable as Time_msg_match? Cause your are saving it in variable X

[Rik]

Since this is a basic Matlab syntax question, I'm wondering if you are asking the question you want the answer to. But if so: of course you can:

Time_msg_match=Time_msg_match(61649);
Time_msg_match=Time_msg_match{1};

Maybe you should have a more explicit explanation of what goal you want to reach and what data you're starting with.

[flashpode]

Okay lets see Time_msg_match is a 311282x1 cell where some of the cells have (2x1 double or 3x1 double). I want them to split¿? in diferent cells so the total number of cells of variable Time_msg_match increase.

I had the same problem with strings and in a post they aswer it. The question is the same but with different data. Here is the post I made:

https://es.mathworks.com/matlabcentral/answers/1455379-separate-strings-that-are-inside-a-cell?s_tid=srchtitle

Hope it helps to understand my problem!!

[Rik]

So something like this?

a={{1,2},3,4};
[a{:}]

ans = 1×4 cell array
    {[1]}    {[2]}    {[3]}    {[4]}

[flashpode]

well a={{1,2} That not a cell it has to be a double,3,4};

[Image Analyst]

@vicente Noguer, did you overlook my request?

https://www.mathworks.com/matlabcentral/answers/1570048-how-to-convert-1x2-double-into-two-1x1#comment_1797268

Also, a specific numerical example using the first 2 or 3 rows of your cell array would be helpful. Help us to help you.

[Rik]

You are ignoring the advice that Image Analyst is giving you. That is not smart.

Also, did you try making a it a double array instead of a cell? You will notice that my code will still do something usefull. It brings you only a single step away from the array you need.