How can I display only the fprintf without the error shown and using "function"

function [category] = iqcategory (score)

%by Manav Divekar, 2021-10-28
%if the given score is greater the 130 
if score >= 130
	fprintf ('Very Superior \n');
elseif score >= 120 && score < 130
	fprintf ('Superior \n');
elseif score >= 109 && score < 120
	fprintf ('High Average \n');
else 
	fprintf ('Average \n');
end

>> disp( iqcategory(112.5) )

High Average

error Output argument "category" (and maybe others) not assigned during call to "iqcategory".

Answer 1

[Image Analyst]

The error is because you said that your function would return category but you never set a value for it, so it's undefined when it comes time to exit your function. So you either have to set it so something (even null if you want):

function category = iqcategory (score)
category = []; % Initialize to null.
%by Manav Divekar, 2021-10-28
%if the given score is greater the 130 
if score >= 130
    fprintf ('A score of %.1f is Very Superior.\n', score);
    category = 'A score of %.1f is Very Superior';
elseif score >= 120 && score < 130
    fprintf ('A score of %.1f is Superior.\n', score);
    category = 'Superior';
elseif score >= 109 && score < 120
    fprintf ('A score of %.1f is High Average.\n', score);
    category = 'High Average';
else 
    fprintf ('A score of %.1f is Average.\n', score);
    category = 'Average';
end

or else just don't bother returning it at all, which means of course you don't set it, or return it, and consequently you won't get the error.

function iqcategory (score)
%by Manav Divekar, 2021-10-28
%if the given score is greater the 130 
if score >= 130
    fprintf ('A score of %.1f is Very Superior.\n', score);
elseif score >= 120 && score < 130
    fprintf ('A score of %.1f is Superior.\n', score);
elseif score >= 109 && score < 120
    fprintf ('A score of %.1f is High Average.\n', score);
else 
    fprintf ('A score of %.1f is Average.\n', score);
end