how to give probability of 90% to unique values of a vector and 10% to repeated values?

Hello, how can I give 90% probability to elements of a vector that do not repeat themselves, and to elements that repeat 10%.

for example:

I have a vector

vector = [10 15 15 23 20 40]

give a probability of 90% to the numbers 10,23,20,40, and a probability of 10% to the numbers that are repeated, that is, 15,15.

and store it in a variable

thanks in advance

[Rik]

Have you already found a way to separate those two groups of numbers? That seems the first step to me. Then you can sample them in a 1:9 ratio.

[giancarlo maldonado cardenas]

separate them in what way?

vector = [10 23 20 40 15 15]

like that?

Answer 1

[Image Analyst]

Did you try a simple for loop?

vector = [10 15 15 23 20 40];
probabilities = zeros(1, length(vector));
for k = 1 : length(vector)
    if sum(vector == vector(k)) >= 2
        % Repeated
        probabilities(k) = 0.1;
    else
        % Not repeated
        probabilities(k) = 0.9;
    end
end
probabilities % Show in command window.

probabilities = 1×6

0.9000 0.1000 0.1000 0.9000 0.9000 0.9000

[giancarlo maldonado cardenas]

hi, i had a problem with your code.

when I put this vector with allocated.mat (attached) list.

I get the following

Operator '==' is not supported for operands of type 'cell'.

Error in MSG3 (line 33)

if sum (allocated == allocated (k))> = 2

you can help?

[Image Analyst]

OK, this is what I got:

s = load('allocated.mat')
allocated = s.allocated
for k = 1 : length(allocated)
    Preambulo(k) = allocated{k}.Preambulo;
    TA(k) = allocated{k}.TA;
    Prb(k) = allocated{k}.Prb;	
end

but I don't know which of these new variables are the variables "vector" and "probabilities" that we were using before.

[giancarlo maldonado cardenas]

you're right I'm very sorry.

the vector variable would be the Preambulo variable.

But with the information you just gave me, I managed to make the code work, thank you.

[Image Analyst]

Oh, OK, great! You're welcome. Thanks for Accepting my Answer. 😃

[giancarlo maldonado cardenas]

Hello my friend how are you? I hope it's ok.

could you help me with this question? https://la.mathworks.com/matlabcentral/answers/1652655-how-can-i-choose-non-repeating-values-with-a-probability-of-90-and-10

is very similar to this question

Thanks in advance