[y,Fs] = audioread('C:\Users\Casper\Desktop\3.3V.wav');
L=length(y); % series length
;
f = Fs/2*linspace(0,1,L/2+1); % single-sided positive frequency
X = fft(y)/L; % normalized fft
PSD=2*abs(X(1:L/2+1)); % one-sided amplitude spectrum
figure,plot(f,PSD);
grid
xlabel('freq(Hz)')
ylabel('amplitude')

 Respuesta aceptada

Star Strider
Star Strider el 28 de Dic. de 2021

1 voto

Try this —
idx = (f <= 1500) & (f <= 1800)
[rpm, freq] = findpeaks(PSD(idx), f(idx), 'MinPeakHeight',0.75E-3)
Without the data, I cannot experiment with that, however it should return the peak value as ‘rpm’ and the frequency as ‘freq’. If it does not, experiment with 'MinPeakProminence' instead of 'MinPeakHeight' since it cannot be determined from the plot that there are not more components to the desired peak.
.

2 comentarios

burak Kalayoglu
burak Kalayoglu el 28 de Dic. de 2021
Thank you king
Star Strider
Star Strider el 28 de Dic. de 2021
As always, my pleasure!
.

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Más respuestas (1)

Voss
Voss el 28 de Dic. de 2021

0 votos

You could use Data Cursor to create a datatip, or you could try something like this:
idx = find(f(:) > 1000 & f(:) < 2500 & PSD(:) > 0.00075);

3 comentarios

burak Kalayoglu
burak Kalayoglu el 28 de Dic. de 2021
Editada: burak Kalayoglu el 28 de Dic. de 2021
I want to find a value1698 (signed point in graph) but ı cant , ı want to find signed point and after ı can find rpm this signal
Voss
Voss el 28 de Dic. de 2021
What does this do?
f(1698)
PSD(1698)
burak Kalayoglu
burak Kalayoglu el 28 de Dic. de 2021
Because I want to see what corresponds to the same psd value in different signals

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Productos

Versión

R2021b

Preguntada:

el 28 de Dic. de 2021

Comentada:

el 28 de Dic. de 2021

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