Evaluate Multiple Conditions in Expression

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Roger Breton
Roger Breton el 9 de En. de 2022
Comentada: the cyclist el 11 de En. de 2022
I've been meaning to simplify my code by combining multiple conditions into one IF statement.
This is what I'm currently using :
if IntX < 1
ah.Color=[1, 1, 1];
xlabel(ax, ' ');
return;
end
if IntX > Inner(3)
ah.Color=[1, 1, 1];
xlabel(ax, ' ');
return;
end
if IntY < 1
ah.Color=[1, 1, 1];
xlabel(ax, ' ');
return;
end
if IntY > Inner(4)
ah.Color=[1, 1, 1];
xlabel(ax, ' ');
return;
end
This is not elegant but it works. I experimented with this statement but I get an error :
if (IntX < 1) && (IntX > Inner(3)) && (IntY < 1) && (IntY > Inner(4))
ah.Color=[1, 1, 1];
xlabel(ax, ' ');
return;
end
  2 comentarios
Torsten
Torsten el 9 de En. de 2022
Use || instead of &&
Voss
Voss el 9 de En. de 2022
If either of IntX and IntY is a vector, you'll get an error using && or ||.

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the cyclist
the cyclist el 9 de En. de 2022
if (IntX < 1) | (IntX > Inner(3)) | (IntY < 1) | (IntY > Inner(4))
ah.Color=[1, 1, 1];
xlabel(ax, ' ');
return;
end
You should also be able to use the short-circuit operator || instead of |.
  2 comentarios
Roger Breton
Roger Breton el 11 de En. de 2022
Editada: Roger Breton el 11 de En. de 2022
Works like a charm -- thank you!
I'm not sure I'm clear on the short-circuit operator : is that, as soon as one condition is false, the whole expression stops being evaluated?
the cyclist
the cyclist el 11 de En. de 2022
You have the gist right, but in the short-circuited OR operation, it will evaluate from left-to-right until it finds a TRUE condition, because then it knows the entire expression is true.
See a fuller explanation in this section of the documentation.

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