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How to do it?

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Negar
Negar el 30 de Nov. de 2014
Comentada: Image Analyst el 30 de Nov. de 2014
Hello all,
Is there any tutorial to learn implementing a flow chart in MATLAB? By flow chart, I mean something like this:
Let´s assume I have a data set, say 24 data points , each of which 2 dimensions. Id like to cluster them in an un pre-defined number of classes. Here is the instruction:
1.FIRST: Find the center(mean) point of the whole dataset. Split this point into 2 center points. Assign each datapoint to the nearest center. 2.NOW: for each center point, repeat point 1 until none of the data points changes its membership. I think it is working in a way similar to kmeans algorithm, but the number of the classes is not defined in advance.
thank you!
  1 comentario
Negar
Negar el 30 de Nov. de 2014
Actually, Im stuck in the very basic part of the algorithm, I don't know how to relate each step to its previous. I have made a try, but it seems my code is not splitting the center point, it just changes its position. Here is my code:
c = [3;2.25]; % the center point of the whole dataset
k = 1 ;
eps = 1e-3;
while k<3
%split the centroid in 2
c(:,k+1) = c(:,k) + eps; % the first one
d(:,k+1) = c(:,k) - eps; % this is not working as expected!! So how to fix it?
k = k+1;
end

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Respuestas (1)

Image Analyst
Image Analyst el 30 de Nov. de 2014
Try these links on machine learning:
Look at the Statistics and Machine Learning section here:
especially the section on unsupervised learning.
  2 comentarios
Negar
Negar el 30 de Nov. de 2014
Thank you for responding, could you please have a look at my code? I can't manage how to store the center points.
Image Analyst
Image Analyst el 30 de Nov. de 2014
I don't know what the code does exactly but it runs without any errors at all:
c = [3;2.25]; % the center point of the whole dataset
k = 1 ;
eps = 1e-3;
while k<3
%split the centroid in 2
c(:,k+1) = c(:,k) + eps; % the first one
d(:,k+1) = c(:,k) - eps; % this works - nothing to fix.
k = k+1;
end
c
d
But you should not use eps as the name of a variable since it's the name of a built in function.

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