Borrar filtros
Borrar filtros

Runge kutta 4th order method for Fitzhugh Nagumo model

4 visualizaciones (últimos 30 días)
Vezzaz
Vezzaz el 4 de Mzo. de 2022
Comentada: Vezzaz el 4 de Mzo. de 2022
So I wrote a runge kutta 4th order code, or what I believe to be one, to solve the fitzhugh-nagumo model equations I was given to solve. I am getting a left side is a 1x1 and the right side is a 2x2 at line 42. I may have done the runge kutta wrong, but I tried changing some things around to make it a 1x1 to a 1x1 but that gave even more errors. Any help would be greatly appreciated, thank you.
clear all
close all
eq1=@(t,x) FN(t,2,0.1,0.1,-0.1);
[x, t] = rk4(eq1,0);
v=x(:,1);
w=x(:,2);
figure(1)
plot(v)
hold on
plot(w)
function dvwdt = FN(~,a,L,e,I) %
x(1)=0; %initial condition for v
x(2)=0; %initial condition for w
v=x(1);
w=x(2);
dvwdt = [I-2*v^2+3*v^2-w; %dv/dt
e*(a*v-L-w)]; %dw/dt
end
function [x, t] = rk4(f, x0)
t0=0; %starting time
dt=0.01; %step size
tf=100; %ending time
t=t0:dt:tf;
nt=numel(t);
nx=numel(x0);
x=nan(nx,nt);
x(:,1)=x0;
for k=1:nt-1
k1= dt*f(t(k),x(:,k));
k2= dt*f(t(k)+dt/2,x(:,k)+k1/2);
k3= dt*f(t(k)+dt/2,x(:,k)+k2/2);
k4= dt*f(t(k)+dt,x(:,k)+k3);
dx=(k1+2*k2+2*k3+k4)/6;
x(:,k+1)= x(:,k)+dx;
end
end

Respuesta aceptada

Benjamin Thompson
Benjamin Thompson el 4 de Mzo. de 2022
Do you need to use x on the first line in the eq1 function that calls FN?
  1 comentario
Vezzaz
Vezzaz el 4 de Mzo. de 2022
I used x because I thought that is what is needed for a differential equation. Also the differential equation is dv/dt and dw/dt so i used dx/dt as a substitute for v and dy/dt as a substitute for w. Which just made things more confusing. But now that I look at it that, x is probably where I went wrong and I am going to try and fix it.

Iniciar sesión para comentar.

Más respuestas (0)

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by