Binary numbers into array

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Rosario Frontino
Rosario Frontino el 27 de Mzo. de 2022
Comentada: Voss el 27 de Mzo. de 2022
I have a string n of N numbers (like '21325231214523234322' ) and their respective Huffman code ( {'10' } {'01' } {'00' } {'110' } {'111' } )
I would like to create an array with all the stream bits (01 10 00 ...)
stream = zeros(1,N);
for i=1:N
value = str2num(n(i));
stream(i) = str2num(ret{3,value});
end
where ret is a cell array with values, probabilities and then the Huffman codes.
This is not working because the codes starting with 0 will be converted to numbers and the 0s are lost (01 -> 0 , 00 -> 0).
Moreover,
stream(i) = ret{3,value};
is also not working: Unable to perform assignment because the left and right sides have a different number of elements.
How can I create my array?

Respuesta aceptada

Rosario Frontino
Rosario Frontino el 27 de Mzo. de 2022
Editada: Rosario Frontino el 27 de Mzo. de 2022
Solved.
If anyone's curious:
bitStream = {};
for i=1:N
value = str2num(n(i));
bitStream(i) = ret(3,value);
end
  1 comentario
Voss
Voss el 27 de Mzo. de 2022
This solution relies on the numbers being integers starting with 1, so that you can use them as indices.
What happens if your numbers are like this? (Hint: an error occurs)
n = '76870786769078789877';
ret = { ...
'6' '7' '8' '9' '0'; ...
0.5 0.3 0.1 0.05 0.05; ...
'10' '01' '00' '110' '111'}
ret = 3×5 cell array
{'6' } {'7' } {'8' } {'9' } {'0' } {[0.5000]} {[0.3000]} {[0.1000]} {[0.0500]} {[0.0500]} {'10' } {'01' } {'00' } {'110' } {'111' }
try
bitStream = {};
N = numel(n);
for i=1:N
value = str2num(n(i));
bitStream(i) = ret(3,value);
end
catch ME
disp(ME.message);
end % error:
Index in position 2 exceeds array bounds. Index must not exceed 5.
No error occurs in this case with my answer:
[~,idx] = ismember(n,[ret{1,:}]);
bitStream = ret(3,idx)
bitStream = 1×20 cell array
{'01'} {'10'} {'00'} {'01'} {'111'} {'01'} {'00'} {'10'} {'01'} {'10'} {'110'} {'111'} {'01'} {'00'} {'01'} {'00'} {'110'} {'00'} {'01'} {'01'}

Iniciar sesión para comentar.

Más respuestas (1)

Voss
Voss el 27 de Mzo. de 2022
Depending on what exactly you're after, one of these two very similar ways may work:
n = '21325231214523234322';
ret = { ...
'1' '2' '3' '4' '5'; ...
0.5 0.3 0.1 0.05 0.05; ...
'10' '01' '00' '110' '111'}
ret = 3×5 cell array
{'1' } {'2' } {'3' } {'4' } {'5' } {[0.5000]} {[0.3000]} {[0.1000]} {[0.0500]} {[0.0500]} {'10' } {'01' } {'00' } {'110' } {'111' }
[~,idx] = ismember(n,[ret{1,:}]);
% 1) stream is a character array of '0's and '1's:
stream = [ret{3,idx}]
stream = '01100001111010010011011011101000100110000101'
% or, 2) stream is a cell array of codewords:
stream = ret(3,idx)
stream = 1×20 cell array
{'01'} {'10'} {'00'} {'01'} {'111'} {'01'} {'00'} {'10'} {'01'} {'10'} {'110'} {'111'} {'01'} {'00'} {'01'} {'00'} {'110'} {'00'} {'01'} {'01'}

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