Find first common element in 2 vectors

I have 2 vectors, A and B, with identical values but in different orders. How do I find the first common element between them? For example, I have 2 vectors as shown below. How would I return the value "25"?

A = [10 25 36 41 53]
B = [53 41 25 10 36]

Thanks in advance for any help!

[Voss]

How do you decide that 25 is the first common element between A and B in the example? Why not 10, for instance?

[KSSV]

REad about ismember.

[ryan]

Sorry for not providing more context; the actual vectors contain over 2000 values so I just put up a small sample. My vectors are indices after using sort. The contents of each vector are different, but the indices correspond to the same observation. In my example, in vector A, index 10 corresponds to the smallest value and in vector B, index 53 corresponds to the smallest value. I want index 25 because it is the first common index that corresponds to one of the smallest values between both vectors. Please let me know if anything else is unclear. Thanks!

[Matt J]

I want index 25 because it is the first common index that is smallest in the two vectors.

No, 10 is smaller than 25.

Answer 1

[David Hill]

for k=1:length(A)
  c=intersect(A(1:k),B(1:k));
  if ~isempty(c)
    break;
  end
end

[ryan]

Thank you! This is exactly what I was looking for!